5 c) Benzoic acid, HC¬H5O2, is a weak monoprotic acid. A stock HC-H;O2 solutionwith unknown concentration was prepared.A 25.00 mL sample of the stock HC,H5O2 solution was titrated with0.1234 M sodium hydroxide to the equivalence point, using phenolphthalein as anindicator. The titration took 20.26 mL of titrant (sodium hydroxide).(c) Write a balanced net ionic equation for the chemical reaction that occurs in thistitration.

The net ionic equation shows ions which are only present directly in the reaction all spectator ions…

Answered: 5 c) Benzoic acid, HC;H5O2, is a weak…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter15: Additional Aqueous Equilibria

Section: Chapter Questions

Problem 93QRT: When 40.00 mL of a weak monoprotic acid solution is titrated with 0.100-M NaOH, the equivalence...

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Phenol, C6H5OH, is a weak organic acid. Suppose 0.515 g of the compound is dissolved in enough water to make 125 mL of solution. The resulting solution is titrated with 0.123 M NaOH. C6H5OH(aq) + OH(aq) C6H5O(aq) + H2O() (a) What is the pH of the original solution of phenol? (b) What are the concentrations of all of the following ions at the equivalence point: Na+, H3O+, OH, and C6H5O? (c) What is the pH of the solution at the equivalence point?
Malonic acid (HO2CCH2CO2H) is a diprotic acid. In the titration of malonic acid w ith NaOH, stoichiometric points occur at pH = 3.9 and 8.8. A 25.00-mL sample of malonic acid of unknown concentration is titrated with 0.0984 M NaOH, requiring 31.50 mL of the NaOH solution to reach the phenolphthalein end point. Calculate the concentration of the initial malonic acid solution. (Sec Exercise 113.)
When 40.00 mL of a weak monoprotic acid solution is titrated with 0.100-M NaOH, the equivalence point is reached when 35.00 mL base has been added. After 20.00 mL NaOH solution has been added, the titration mixture has a pH of 5.75. Calculate the ionization constant of the acid.
Sketch two pH curves, one for the titration of a weak acid with a strong base and one for a strong acid with a strong base. How are they similar? How are they different? Account for the similarities and the differences.
A 20.00 mL aliquot of lactic acid solution (HCH3H5O3) was titrated with 0.0980 M KOH(aq) using both an indicator and a pH meter. Ka (HCH3H5O3), is 1.38 x10-4. A total of 28.64 mL of 0.0980 M KOH(aq) was required to reach the equivalence point 1. Calculate the molarity of the lactic acid solution. 2. Calculate the pH of the lactic acid solution 3. Calculate the pH and [CH3H5O3-] at the half-equivalence point. 4. Calculate the pH at the equivalence point of the titration. 5. Suggest an appropriate indicator for titration. 6. Calculate the pH of the solution after 10.00 mL of 0.0980 M NaOH(aq) was added
A 20.00 mL aliquot of sorbic acid solution (HC6H7O2) was titrated with 0.0985 M NaOH * (aq) using both an indicator and a pH meter. Ka (HC6H7O2) , is 1.7*10^ -5 . A total of 25.34 mL of 0.0985 M NaOH * (aq) was required to reach the equivalence point a) Calculate the molarity of the sorbic acid solution. b) Calculate the pH of the sorbic acid solution (use the RICE table) . c) .Calculate the pH and [C6H 7 O 2-] at the half-equivalence point . d) Calculate the pH at the equivalence point of the titration . (use Kb for hydrolysis of sorbate anion and RICE table ). e)Suggest an appropriate indicator for titration . Explain your choice . f) Calculate the pH of the solution after 10.00 mL of 0.0985 M NaOH * (aq) was added . (find moles of sorbic acid and sorbate and use Henderson Haselbalch equation ) Indicator pKa Phenolphthalein 9.3 Bromothymol blue 7.0 Methyl red. 5.0 Thymol blue. 2.0 Methyl violet…
Potassium hydrogen phthalate (KHPKHP) is often used as a primary standard in acid–base titrations. If 20.05 mL NaOH20.05 mL NaOH is required to neutralize 0.397 g KHP,0.397 g KHP, what is the concentration of the NaOH?
A weak base, ammonia, is to be titrated with hydrochloric acid. A volume of 30.0 mL of the 0.75 M NH3 (weak base) whose Kb = 5.25 x10^-6 is titrated with 0.96 M HCl (strong monoprotic acid). Assuming that the stoichiometry for this neutralization titration is 1:1 , calculate the ff: A. pH of the resulting solution when the volume of the added strong acid titrant neutralizes 70% of the analyte. B. pH of the resulting solution at the equivalence point. C. pH of the resulting solution at 5.0 ml added titrant beyond the equivalence point.
ssume you dissolve 0.235 g of the weak acid benzoic acid, C6H5CO2H, in enough water to make 7.00 ✕ 102 mL of solution and then titrate the solution with 0.153 M NaOH. C6H5CO2H(aq) + OH-(aq) C6H5CO2-(aq) + H2O(ℓ) What are the concentrations of the following ions at the equivalence point? Na+, H3O+, OH-C6H5CO2- M Na+ M H3O+ M OH- M C6H5CO2-
Benzoic acid, C6H5COOH, dissociates in water as shown in the equation below. A 40.0 mL sample of an aqueous solution of benzoic acid with a concentration of 0.50 M is titrated using standardized 0.25 M NaOH. C6H5COOH(s) -> C6H5COO–(aq) + H+(aq) Ka = 6.46 x 10^-5 Calculate the pH of the solution after the following amounts of NaOH have been added… A. 0 mL B. 10 mL C. 85 mL
In order to standardize a solution of NaOH, 1.05 mL of NaOH is titrated with 0.100 M oxalic acid (H2C2O4). If 295 µL of oxalic acid is needed to reach the endpoint, what is the molarity of the NaOH solution?
The weak monoprotic acid, acetic acid, is titrated with the strong base, potassium hydroxide as follows: HC2H3O2(aq) + K+ OH- (aq) → K+ C2H3O2-(aq) + H2O(l) Ka for acetic acid is 1.81 x 10-5 (at 25 oC). A 25.00 mL sample of a solution of acetic acid with concentration 0.0833 M is titrated with 0.1000 M KOH. a) Sketch the pH vs volume of added base titration curve for this reaction. pH vertically, volume of base horizontally. Label your axes with correct pH and volumes. (Attach more space, if needed) b) what is the pH at the beginning of the titration, Vbase = 0.00 mL ? c) what is the volume of the base needed to reach the equivalence point ? (label the equiv. point) d) what is the pH at the equivalence point?e) what is the pH of the titration when 5.00 mL of base have been added ? f) what is the pH when the volume of base added equals half the volume of the equivalence point? g) what is the pH of the titration when 20.00 mL of base have been added? h) what is the pH of the titration…

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