5) One silver electrode in 246 ml of 0.100 M AgNO3 solution and one in 188 ml of 0.100 M Mg (NO3)2 solution A galvanic cell was formed by dipping the magnesium electrode. a) E value of the cell at 25 ° C calculate. b) Since the current is generated at the silver electrode until 2.10 g of silver is collected, www cell potential, find the value of E. E°Mg2+/Mg -2,37 V; E°Ag+/Ag = 0,800 V %3D %3D

Fundamentals Of Analytical Chemistry
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Chapter18: Introduction To Electrochemistry
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5)
One silver electrode in 246 mL of 0.100 M AGNO3 solution and one in 188 ml of 0.100 M Mg (NO3)2
solution
A galvanic cell was formed by dipping the magnesium electrode.
a)
E value of the cell at 25 ° C calculate.
wwww
b)
Since the current is generated at the silver electrode until 2.10 g of silver is collected,
cell potential, find the value of E.
E°Mg2+/Mg = -2,37 V; E°Ag+/Ag = 0,800 V
Transcribed Image Text:5) One silver electrode in 246 mL of 0.100 M AGNO3 solution and one in 188 ml of 0.100 M Mg (NO3)2 solution A galvanic cell was formed by dipping the magnesium electrode. a) E value of the cell at 25 ° C calculate. wwww b) Since the current is generated at the silver electrode until 2.10 g of silver is collected, cell potential, find the value of E. E°Mg2+/Mg = -2,37 V; E°Ag+/Ag = 0,800 V
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