A concentration cell based on the following half reaction at 288 K Ag +e Ag; SRP = 0.80V is made from two 1.00 L solutions of Aqt, 1.4 M and 0.354 M; two 100.0g pieces of Ag metal, a wire, and a salt bridge. Under these conditions the potential of the cell is 0.034121 V. How much Ag metal will need to be oxidized for the potential of the cell to decrease by 0.022301 V?

Chemistry: An Atoms First Approach
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Author:Steven S. Zumdahl, Susan A. Zumdahl
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Chapter17: Electrochemistry
Section: Chapter Questions
Problem 135CWP: Consider a galvanic cell based on the following half-reactions: a. What is the expected cell...
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A concentration cell based on the following half reaction at 288 K
Ag +e
- Ag; SRP = 0.80V
is made from two 1.00 L solutions of Agt, 1.4 M and 0.354 M; two 100.0 g pieces of Ag metal, a wire, and a
salt bridge. Under these conditions the potential of the cell is 0.034121 V. How much Ag metal will need to be
oxidized for the potential of the cell to decrease by 0.022301 V?
Give your answer to 3 decimal places.
(g)
number (rtol=0.01, atol=1e-08)
Transcribed Image Text:A concentration cell based on the following half reaction at 288 K Ag +e - Ag; SRP = 0.80V is made from two 1.00 L solutions of Agt, 1.4 M and 0.354 M; two 100.0 g pieces of Ag metal, a wire, and a salt bridge. Under these conditions the potential of the cell is 0.034121 V. How much Ag metal will need to be oxidized for the potential of the cell to decrease by 0.022301 V? Give your answer to 3 decimal places. (g) number (rtol=0.01, atol=1e-08)
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