5. The following 3-point test cross is conducted and produces the listed progeny genotypes and numbers: АВС х аbc abc abc 300 Total Progeny: АВС 117 abc 111 abc abc Abc 10 aBC 12 abc bc АВс 27 abC 20 abc abc aBc abc AbC 2 1 abc a) Using the annotation NR to indicate non-recombinant, 1° R to indicate single crossover recombinant, and 2° R to indicate double crossover recombinant, label each progeny group listed above. b) Determine and write the correct order of these 3 genes on the chromosome. c) Calculate the map distances between the 3 genes to 3 decimal places and round to the second decimal place and construct a correctly labeled and proportioned map that includes the distances, Show all calculations!

5. The following 3-point test cross is conducted and produces the listed progeny genotypes and numbers: АВС х аbc abc abc 300 Total Progeny: АВС 117 abc 111 abc abc Abc 10 aBC 12 abc bc АВс 27 abC 20 abc abc aBc abc AbC 2 1 abc a) Using the annotation NR to indicate non-recombinant, 1° R to indicate single crossover recombinant, and 2° R to indicate double crossover recombinant, label each progeny group listed above. b) Determine and write the correct order of these 3 genes on the chromosome. c) Calculate the map distances between the 3 genes to 3 decimal places and round to the second decimal place and construct a correctly labeled and proportioned map that includes the distances, Show all calculations!

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter12: Mendel's Experiments And Heredity

Section: Chapter Questions

Problem 18RQ: The forked line and probability methods make use of what probability rule? test cross product rule...

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1. a) If you were at risk of a fatal disease such as Huntington’s disease and only the 95% accurate preliminary genetic test was available, would you take the test? After all, 95% of the time the test would tell you whether you would eventually get Huntington’s disease or whether you did not have to worry about getting this disease. b) The linkage distance between the DNA sequence used in the test and the actual Huntington’ disease locus was 5%. In a large sample of the Venezuelan family, what percentage of people would inherit the DNA sequence but not the Huntington’s allele (i.e. be a false positive test for Huntington’s)? What percentage of that large Venezuelan family would not inherit the DNA sequence but would inherit the Huntington’s allele (i.e., be a false negative test for Huntington’s)?
1. The first genetic test used a short DNA sequence that was closely linked to the Huntington’s locus. The linkage distance between the DNA sequence used in the test and the actual Huntington’ disease locus was 5%. a. In a large sample of the Venezuelan family (over 2,000 individuals), what percentage of people would inherit the DNA sequence but not the Huntington’s allele (i.e. be a false positive test for Huntington’s)? b. What percentage of that large Venezuelan family would not inherit the DNA sequence but would inherit the Huntington’s allele (i.e., be a false negative test for Huntington’s)?
16.A couple is suspecting that their baby was switched at the hospital. The mother has blood type A, the father has blood type B, and the baby has blood type O. Which among the following conditions would prove that the baby is switched? A. Mother’s genotype: IAIA & Father’s genotype: ii B. Mother’s genotype: ii & Father’s genotype: IBIB C. Mother’s genotype: IAIA & Father’s genotype: IBIB D. Mother’s genotype: IAi & Father’s genotype: IBi
The genotype XXY corresponds to Klinefelter syndrome Turner syndrome Triplo-X Jacob syndrome
The forked line and probability methods make use of what probability rule? test cross product rule monohybrid rule sum rule
A testcross is a way to determine ________. a. phenotype b. genotype c. dominance
Klinefelter syndrome (XXY) can most be easily diagnosed by _______. a. pedigree analysis. b. aneuploidy c. karyotyping d. phenotypic treatment
Which recombination frequency corresponds to perfect linkage and violates the law of independent assortment? 0 0.25 0.50 0.75
1) By decomposing the cross, MmNn X Mmnn, into single gene outcomes, the possibility of obtaining a double recessive outcome for the ‘N’ gene is: a) 50%! b) 100! c) 0%! d) 25%! 2) A 16-square Punnett is time-consuming to draw out. Dr. Thompson can easily solve this problem by decomposing her dihybrid crosses into separate monohybrid Punnett squares, which would also be quicker than using a forked line diagram. If so, how many individual monohybrid Punnett squares will she need to draw? a) Four Punnett squares. b) Two Punnet squares. c) One Punnett square. d) Sixteen Punnett squares since there are 16 possible outcomes.
11. Shown below are the offspring of the testcross qr/q +r+ X q r/q r. Which groups are in the recombinant class? q+r and qr+ q+r+ and qr+ qr and qr+ q+r+ and qr
1. a. Examine the following image showing the results of an ALU insert gel-like. The first lane is the molecular marker. How many + alleles are represented in lanes 2-8? Assume each lane is an individual's amplified diploid DNA. b.The first lane is the molecular marker. How many - alleles are represented in lanes 2-8? Assume each lane is an individual's amplified diploid DNA. c.The first lane is the molecular marker. If lanes 2-8 represent the seven students in the class, what is the frequency of the + allele in this small population? d. If this gel represents the genotypes of all 7 students in a class, what is the EXPECTED number of people that would have a +/+ genotype if this small population were in Hardy-Weinberg equilibrium? (To nearest tenth)
1.If the AaBBCc individual will be test-crossed, what is the probability that the resulting offspring will show all the recessive traits? a.three-fourth b.zero c.nine-sixteenth d.one-sixteenth 2. Who conclusively demonstrated that the substance responsible for the transformation of non-virulent Streptococcus pneumoniae to virulent S. pneumoniae is the DNA? a.Frederick Griffith b.Hershey and Chase c.Watson and Crick d.Avery, MacLeod, and McCarthy