52 grams of CuCl2 are reacted with 192 grams of NaNO3.How many moles of NaCl are produced? Answer to twodecimal places. (Hint: find the limiting reactant first!)CuCl2 + 2 NaNO3 Cu(NO3)2 + 2 NaClCuCl, = 134.45 g/molNaNO3 = 84.99 g/mol

Answered: 52 grams of CuCl2 are reacted with 192…

World of Chemistry, 3rd edition

3rd Edition

ISBN:9781133109655

Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Chapter9: Chemical Quantities

Section: Chapter Questions

Problem 71A

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52 grams of CuCl2 are reacted with 192 grams of NaNO3.
How many moles of NaCl are produced? Answer to two
decimal places. (Hint: find the limiting reactant first!)
CuCl2 + 2 NaNO3 Cu(NO3)2 + 2 NaCl
CuCl, = 134.45 g/mol
NaNO3 = 84.99 g/mol

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Step 1

$g i v e m a s s o f C u C l_{2} = 52 g m o l a r m a s s o f C u C l 2 = 134.45 g t h e r e f o r e, n o o f m o l e s o f C u C l_{2} = \frac{g i v e n m a s s}{m o l a r m a s s} = \frac{52}{134.45} = 0.3867 m o l e = 0.39 m o l e a l s o, g i v e n m a s s o f N a N O_{3} = 192 g m o l a r m a s s o f N a N O_{3} = 84.99 g n o o f m o l e s o f N a N O_{3} = \frac{g i v e n m a s s}{m o l a r m a s s} = \frac{192}{84.99} = 2.259 o r = 2.26 m o l e$

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