**52. The drawing shows a container that is partially filled with 2.0 gramsof water. The temperature is maintained at a constant 20 °C. The spaceabove the liquid contains air that is completely saturated with water vapor.A tube of length 0.15 m and cross-sectional area 3.0 X 10-ª m² connectsthe water vapor at one end to air that remains completely dry at the otherend. The diffusion constant for water vapor in air is 2.4× 10-5 m²/s. Howlong does it take for the water in the container to evaporate completely?(Hint: Refer to Problem 75 in Chapter 12 to find the pressure of the watervapor.)- 0.15 m-Water- Dry airvaporLiquid water

Given: Mass of water = 2 g =2×10-3 kg Temperature = 20° C = 293.15 K Length of tube L =0.15 m Cross…

Answered: **52. The drawing shows a container…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter16: Temperature And The Kinetic Theory Of Gases

Section: Chapter Questions

Problem 13OQ

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Review Conceptual Example 6 before working this problem. For water vapor in air a 293 K, the diffusion constant is D = 2.4 x 10-5 m2/s. As outlined in Problem 51(a), the time required for the first solute molecules to traverse a channel of length L is t = L2/(2D), according to Fick's law. (a) Find the time t for L = 0.0460 m. (b) For comparison, how long would a water molecule take to travel L = 0.0460 m at the translational rms speed of water molecules (assumed to be an ideal gas) at a temperature of 293 K?
You can smell perfume very shortly after opening the bottle. To show that it is not reaching your nose by diffusion, calculate the average distance a perfume molecule moves in one second in air, given its diffusion constant D to be 1.00 • 10–6 m2/s.Numeric : A numeric value is expected and not an expression.xrms = __________________________________________
An expandable cylinder has its top connected to a spring with force constant 2.00 x 103 N/m (Fig. P10.64). The cylinder is filled with 5.00 L of gas with the spring relaxed at a pressure of 1.00 atm and a temperature of 20.0°C. (a) If the lid has a cross-sectional area of 0.0100 m2 and negligible mass, how high will the lid rise when the temperature is raised to 250°C? (b) What is the pressure of the gas at 250°C?
Oxygen reaches the veinless cornea of the eye by diffusing through its tear layer, which is 0.48-mm thick. How long does it take the average oxygen molecule to do this? The diffusion constant is 1.0 • 10-9 m2/s)Numeric : A numeric value is expected and not an expression.t = __________________________________________
The classic Goodyear blimp is essentially a helium balloon— a big one, containing 5700 m3 of helium. If the envelope and gondola have a total mass of 4300 kg, what is the maximum cargo load when the blimp flies at a sea-level location? Assume an air temperature of 20°C.
15.01 A cylindrical tank has a tight-fitting piston that allows the volume of the tank to be changed. The tank originally contains 0.100 m3m3 of air at a pressure of 3.10 atm. The piston is slowly pulled out until the volume of the gas is increased to 0.390 m3 . If the temperature remains constant, what is the final value of the pressure? Express your answer in atmospheres.
A tire with an inner volume of 0.025 m^3 is filled with air at a gauge pressure of 36psi. If the tire valve is opened to the atmosphere, what volume outside of the tire does the escaping air occupy? Some air remains within the tire occupying the original volume, but now that remaining air is at atmospheric pressure. Assume the temperature of the air does not change. a. 0.086 m^3b. 0.096 m^3c. 0.868 m^3d. 0.673 m^3
A sealed cubical container contains helium gas at a temperature of 22.5°C. What is the average velocity of one of these helium atoms? A helium atom has a mass of 6.64x10-27 kg kB = 1.38 x 10-23 J/K
Estimate the time required for oxygen to diffuse from our nose to our lungs. Assume the diffusion constant of oxygen in air is 2×10^(-5) m^2 s^(-1) and the distance from the nose to the lungs in a human is about 20 cm. a. 0.1 min. b. 17 min. c. 21 min. d. 0.01 min.
The outer diameter of a glass jar and the inner diameter of its iron lid are both 760 mm at room temperature (20.0 ∘C). a)What will be the size of the mismatch between the lid and the jar if the lid is briefly held under hot water until its temperature rises to 57.5 ∘C, without changing the temperature of the glass? Use the coefficient of linear expansion for iron α=1.2×10−5K−1.
What is human body temperature in Fahrenheit and Celsius? A) 98.6 f and 37 c B) 100 f and 212 c C) 212 f and 100 c D) 37 f and 98.6 c

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