Question
Asked Jul 16, 2019
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53.5 g of an ideal gas of molecular weight = 30.5 g/mol are confined at a pressure of 133 mmHg. The density of the gas is 0.228 g/L. Compute the temperature of the gas in degrees Celsius.

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Expert Answer

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Step 1

According to ideal gas equation

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PV nRT Where P isthepres sure V =is thevolume =is the number of moles of the gas R 0.0821L.atmKmolisthegas con tan t T Temperature

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Step 2

Apply the ideal gas equation to find the temperature of the gas using the equation

Putting 

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PV T nR PV nRT Where P 133mmHg 0.175 atm 53.5g234.65L V= 0.228 L 53.5g -1.75moles n 30.5 g mole R 0.0821LatmKmolisthe gas con tan t

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Step 3

Substituting all the giv...

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PV T = n R T (0.175atm)(234.65 L) (1.75moles)(0.0821atm Kmole T 285.80K =285.80- 273 =12.8° C

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Chemistry

Ideal gases

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