53°F Partly sunny H Q Search the air follows an adiabatic saturation curve (constant compared wet-bulb temperature line) on the psychrometric chart. 1. Air at 30°C, 10% relative humidity Figure 8.4-1 h,= 0.0026 kg H₂O/kg DA TwbT13.2°C 2. The state of the outlet air must lie on the Tb 13.2°C line. From the intersection of this line with the curve for h, = 40%, the absolute humidity of the exit gas is determined to be 0.0063 kg H₂O/kg DA. The inlet (and outlet) flow rate of dry air, mp, is DA(1000 kg air/h)(1 kg DA/1.0026 kg air) 997.4 kg DA/h The amount of water that must be evaporated, mo, may be calculated as the difference between the outlet and inlet water flow rates in the air stream. ^ENG

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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For 1, locate the absolute humidity and the web-bulb temperature.  

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Example 8.4-7
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Adiabatic Humidification
mbarmes
A stream of air at 30°C and 10% relative humidity is humidified in an adiabatic spray tower operating at
P≈ 1 atm. The emerging air is to have a relative humidity of 40%.
H₂O (1)
Air, 30°C, h, = 10%
CD
Figure 8.4-1
ha = 0.0026 kg H₂O/kg DA
Twb Tas 13.2°C
Humidified air
h, = 40%
SPRAY
TOWER
1. Determine the absolute humidity and the adiabatic saturation temperature of the entering air.
2. Use the psychrometric chart to calculate (i) the rate at which water must be added to humidify
1000 kg/h of the entering air, and (ii) the temperature of the exiting air.
H₂O (1)
We assume that the heat required to raise the temperature of the liquid in the spray tower is negligible
compared with the heat of vaporization of water, so that the air follows an adiabatic saturation curve (constant
wet-bulb temperature line) on the psychrometric chart.
1. Air at 30°C, 10% relative humidity
H
2. The state of the outlet air must lie on the Twb = 13.2°C line. From the intersection of this line with the
curve for hr = 40%, the absolute humidity of the exit gas is determined to be 0.0063 kg H₂O/kg DA.
The inlet (and outlet) flow rate of dry air, MDA, is
MDA = (1000 kg air/h)(1 kg DA/1.0026 kg air) = 997.4 kg DA/h
The amount of water that must be evaporated, mH₂o, may be calculated as the difference between the
outlet and inlet water flow rates in the air stream.
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Transcribed Image Text:||! PDF Elementary Principles of Chemica X PDF *Elementary Principles of Chemic X + 53°F Partly sunny File | E:/Elementary%20Principles%20of%20Chemical%20Processes,%204th%20Edition%20(%20PDFDrive%20).pdf Draw T Read aloud Example 8.4-7 Equipment Encyclopedia humidifer-water spray www.wiley.com/college/felder Solution Q Search 461 of 695 Adiabatic Humidification mbarmes A stream of air at 30°C and 10% relative humidity is humidified in an adiabatic spray tower operating at P≈ 1 atm. The emerging air is to have a relative humidity of 40%. H₂O (1) Air, 30°C, h, = 10% CD Figure 8.4-1 ha = 0.0026 kg H₂O/kg DA Twb Tas 13.2°C Humidified air h, = 40% SPRAY TOWER 1. Determine the absolute humidity and the adiabatic saturation temperature of the entering air. 2. Use the psychrometric chart to calculate (i) the rate at which water must be added to humidify 1000 kg/h of the entering air, and (ii) the temperature of the exiting air. H₂O (1) We assume that the heat required to raise the temperature of the liquid in the spray tower is negligible compared with the heat of vaporization of water, so that the air follows an adiabatic saturation curve (constant wet-bulb temperature line) on the psychrometric chart. 1. Air at 30°C, 10% relative humidity H 2. The state of the outlet air must lie on the Twb = 13.2°C line. From the intersection of this line with the curve for hr = 40%, the absolute humidity of the exit gas is determined to be 0.0063 kg H₂O/kg DA. The inlet (and outlet) flow rate of dry air, MDA, is MDA = (1000 kg air/h)(1 kg DA/1.0026 kg air) = 997.4 kg DA/h The amount of water that must be evaporated, mH₂o, may be calculated as the difference between the outlet and inlet water flow rates in the air stream. {" J 63 50 ENG Sign in (0) 7:26 AM 5/19/2023 + □ {0}
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