6) In the given Fig. 2, the butt-welded joint is subjected to uniaxial tensile load of 10 kN, with throat thickness of 5 mm and length of the weld as 100 mm. So calculate the tensile stress generated for each weld plates? N.B. The butt joint efficiency is 90% Fig. 2
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A: As per the guidelines I am able to answer one question Only. So please repost the remaining question…
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- A GTAW operation is performed on low carbon steel, whose unit melting energy is 10.3 J/mm3. The welding voltage is 22 volts and the current is 135 amps. The heat transfer factor is 0.7 and the melting factor is 0.65. If filler metal wire of 3.5 mm diameter is added to the operation, the final weld bead is composed of 60% volume of filler and 40% volume base metal. If the travel speed in the operation is 5 mm/sec, determine (a) cross-sectional area of the weld bead, and (b) the feed rate (mm/sec) at which the filler wire must be supplied.An RSW operation is used to join two pieces of sheet steel having a unit melting energy of 8369.85 J/cm3. The sheet steel has a thickness of 0.3125 cm. The weld duration will be set at 0.25 sec with a current of 11,000 amp. Based on the electrode diameter, the weld nugget will have a diameter of 0.75 cm. Experience has shown that 40% of the supplied heat melts the nugget and the rest is dissipated by the metal. If the electrical resistance between the surfaces is 130 micro-ohms, what is the thickness of the weld nugget assuming it has a uniform thickness?The welding parameters to be used to butt weld a metal alloy are being evaluated. In order to set up the welding machine, the melting factor for the metal (f2) has to be determined. The welding machine can deliver 4000 watts of power and the heat transfer factor for the welding process (f1) is 0.9. The final weld bead consists of 8 0% filler metal and 40% parent metal. The melting temperature of the filler metal and the parent metal is the same 2540 deg F. The cross-sectional area of the weld bead is 0.5 sq inches. The rate at which filler metal is added to the weld is 1 cu inch per min. Conversion factor 1 Btu = 1055 J and 0 deg F = 460 deg R Calculate the melting factor.
- a) list two advantages and two disadvantages of welded joints b) Name the type of bonding forces applied in welded joints A plate 50mm wide by 11mm thick is joined with another plate 120mm wide by 11mm thick by parallel welds of 40mm long.if the permissible tensile and shear stresses are 110MPa and 80MPa respectively calculate; i) safe load F carried by the joint ii) Efficiency of the jointTe - Effective throat thickness well in mm = 6 sin45° Consider the following drawing in which plate 1 is welded onto plate 2 as shown for tensile and shear loading. The plates are fillet welded with a weld thickness of 6 mm as shown for a length of 150 mm. The plates have an ultimate strength of 275 MPa and the welding was done with F70 welding electrodes, which possesses an ultimate strength of 483 MPa. Consider a partial factor of safety of 1.7 for the welded joint and determine the design strength of the weld joint, both in tension (Tdw) and in shear (Vdw) due to the forces acting on it. a) Determine the design strength of the following weld in tension ( ) due to vertical forces. b) Determine the design strength of the weld in shear ( ) due to horizontal forces. Attached pic is shear equation for calculation Tension equation for calculation is: Tdw = FyLwte /YmwQuestion: a) A plate 100 mm wide and 10 mm thick is to be welded to another plate by means of double parallel fillets. The plates are subjected to a static load of 80 kN. Find the length of weld if the permissible shear stress in the weld does not exceed 55MPa. Determine the increase in load carrying capacity if a combination of single transverse double parallel fillet is used the permissible tensile strength of material is 80MPa. b) Draw a neat sketch of double riveted double cover but joint. If 8mm plates with 20 mm diameter rivets having a pitch of 50 mm are joint using double riveted lap joint. The permissible stresses are permissible tensile stress = 120 MPa;Permissible crushing stress= 100 MPa; Permissble shear stess= 150 MPa. Find the strengths and efficiency of joint, taking the strength of the rivet in double shear acoording to the indian boiler standards.
- Question 41. Two 10-mm-thick by 60-mm wide hot rolled SAE 1050 steel plates are to be butt-welded together with a CJP weld. Choose an appropriate electrode for tensile loading of the joint. 2. Find the torque that a 2-surface dry disk clutch can transmit if the outside and inside lining diameters are 120 mm and 70 mm, respectively, and the applied force is 10 kN. Assume uniform wear and μ = 0.4.Dynamic forces F1 = 4000N and F2 = 6000N are applied to the welded part shown in the figure as shown below. For dynamic forces, both dynamics are synchronized, and when the force in the y-axis direction is downward, it is on the right in the x-axis direction. When the force is up, the other force is on the left. The welded part is made of 1018 HR steel, 10 mm thick. a) Safety factor for welding? b) Calculate the safety factor for the base metal. (Electrode type for question is E9010.)A U-groove weld is used to butt weld 2 pieces of 7.0-mm-thick titanium plate. The U-groove is prepared using a milling cutter so the radius of the groove is 3.0 mm. During welding, the penetration of the weld causes an additional 1.5 mm of material to be melted. The final cross-sectional area of the weld can be approximated by a semicircle with a radius of 4.5 mm. The length of the weld is 200 mm. The melting factor of the setup is 0.57 and the heat transfer factor is 0.86. (a) What is the quantity of heat (in Joules) required to melt the volume of metal in this weld (filler metal plus base metal)? Assume the resulting top surface of the weld bead is flush with the top surface of the plates. (b) What is the required heat generated at the welding source?
- The unit melting energy for a certain sheet metal is 10J/mm^3 .The thickness of each of the two sheets to be spot-welded is = mm. To achive required strength, it is desired to form a weldnugget that is =7 mm in diameter and 3.5 mm thick. The weld duration will be set at 44 sec .If the electrical resistance between the two surfaces is 144 micro-ohms and only one half the electricity generated will be used to form the weld nugget Determine the minium current level required in this operationA tension plate shown below is used to support suspended load "T". Gusset Plate F, = 248 MPa Fu = 400 MPa 200 mm. Determine the allowable tensile capacity of the plate if L= 240 mm. (Assume weld strength is satisfactory)Can a tee weld be strong if the welds on both sides do not have deep penetration? Why or why not?