6. 2/4 points | Previous Answers LarCAABLS2 3.4.034.MI 1/6 Submissions UsedMy Notes Ask Your TeacherUse the Intermediate Value Theorem to show that the function has at least one zero in the interval [a, b]. (You do not have to approximate the zero.)x) - 5x 7, I-2, -1]k-2) ,-23Because K-2) isnegativeand-1) is positive▼、, the function has a zero in the interval [-2.-11.Need Help? aWatchMatTal to TuterRead ItMaster It
6,
![6. 2/4 points | Previous Answers LarCAABLS2 3.4.034.MI 1/6 Submissions Used
My Notes Ask Your Teacher
Use the Intermediate Value Theorem to show that the function has at least one zero in the interval [a, b]. (You do not have to approximate the zero.)
x) - 5x 7, I-2, -1]
k-2) ,-23
Because K-2) is
negative
and
-1) is positive
▼、, the function has a zero in the interval [-2.-11.
Need Help? aWatchMatTal to Tuter
Read It
Master It](https://prod-qna-question-images.s3.amazonaws.com/question/51904d57-3265-4334-9bef-5464987a032e/01ceff06-f6dd-4516-8e65-d33c679e054e/xx4o8p.png)
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6. 2/4 points | Previous Answers LarCAABLS2 3.4.034.MI 1/6 Submissions Used My Notes Ask Your Teacher Use the Intermediate Value Theorem to show that the function has at least one zero in the interval [a, b]. (You do not have to approximate the zero.) x) - 5x 7, I-2, -1] k-2) ,-23 Because K-2) is negative and -1) is positive ▼、, the function has a zero in the interval [-2.-11. Need Help? aWatchMatTal to Tuter Read It Master It
To show the existence of a solution to the given equation f(x)=0 over the given interval
The problem is concerned with applying the intermediate value theorem: If f(x) is a continuous function on an interval [a,b] and if f(a) and f(b) have opposite signs, then there exists a point c in [a,b] such that f(c)=0. (See the graphical interpretation)
Apply the intermediate value theorem to our function f(x)=x^5-5x+7 over the interval [-2.-1]. f(x) ...
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Algebra
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