6. Calculate Kc for 2N,O4e) + 30zle) → 2N,0 (2 K=? using. (E) Reaction 1 2N218) + Ozle) * 2N,0 (e) K, = 1.2 x 10 35 Reaction 2 - 2NO2 (e) K2 = 4.6 x 103 Reaction 3 ½ Nze) + O2le) → NO2(e) K3 = 4.1 x 10

Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 95AP
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6. Calculate Kc for
2N204(6) + 3021e) - 2N20 (e) K=?
using..
Reaction 1
2N2e) + O2le)
- 2N,0 (2)
K, = 1.2 x 1035
2NO2 (6)
K2 = 4.6 x 103
Reaction 2
½ N21e) + O218)
e NO2 (2)
K3 = 4.1 x 10°
Reaction 3
Transcribed Image Text:6. Calculate Kc for 2N204(6) + 3021e) - 2N20 (e) K=? using.. Reaction 1 2N2e) + O2le) - 2N,0 (2) K, = 1.2 x 1035 2NO2 (6) K2 = 4.6 x 103 Reaction 2 ½ N21e) + O218) e NO2 (2) K3 = 4.1 x 10° Reaction 3
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