1. Is there a difference between the values of the nozzle velocity (vn) and the jet velocity (v₁)? Why?

Principles of Foundation Engineering (MindTap Course List)
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ISBN:9781305081550
Author:Braja M. Das
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Chapter14: Sheet-pile Walls
Section: Chapter Questions
Problem 14.9P
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6. Discussion:
1. Is there a difference between the values of the nozzle velocity (vn) and
the jet velocity (v₁)? Why?
2. Is there a difference between the values of the water jet force on plate
(F₁) when change the plate shape (flat, Conical, and Hemispherical plate)?
Why?
3. Is there a difference between the values of the water jet force on plate
(F₁) and the force exerted by weights on fluid (Fexp)? Why?
4. What is the relationship type in the plot between (Fexp) versus (p Qv₁)?
Why?
5. Is there a difference between the slope from plot and the slope of the
value (1- Cose)? Why?
Transcribed Image Text:6. Discussion: 1. Is there a difference between the values of the nozzle velocity (vn) and the jet velocity (v₁)? Why? 2. Is there a difference between the values of the water jet force on plate (F₁) when change the plate shape (flat, Conical, and Hemispherical plate)? Why? 3. Is there a difference between the values of the water jet force on plate (F₁) and the force exerted by weights on fluid (Fexp)? Why? 4. What is the relationship type in the plot between (Fexp) versus (p Qv₁)? Why? 5. Is there a difference between the slope from plot and the slope of the value (1- Cose)? Why?
Calculation
time = 28, Volume = 5, mass: 70, h = 5. __
VOL
5
1=0.17 m²/sec
(V₁ = = 0.17
time
28
12.56
A = I ² = = ~(4) = 12.56 m² / V5= Vn -√2gh
= 0.013-√2016)
=83.64
FJ=9Q VJ (1-cose)
=(1/(0-17) (83.64) (1-C0545)
= 4.265
90-45, time = 32, Volume = 5, mass=140
/V₁=
Q = Vol = 5= 0.15 m²/sie
tim 32
..15
12.56
A=Id=-(6)=12.56² / V5= Vn -√2gh
=0.011-√√2x 140.50
= 118.3
FJ=A@v₂ (1-cosys)
=(1)(0.15) (118.3) (0.31
= 5.323
J
0=45
= 0.013 mhu
h: 50mm
= 0.011 m/s.c
Calculation
D 0=9 time=19, mass: 1oo, ho 50mm, Volume 5
Vol 50.26 m²/see
time 19
/ Vni
V₁ = @=
0.26
12.56
A= d² = (16) = 12.56 m² / V5= V₁-√2gh
=0.02-√2x100 50
= 100
FJ=PQV₂ (1-C059)
=(1) (0-26) (100) (1-0)
= 26
90-9:
time = 23, mass = 70, h = 50mm, Volum. 5
VOL
5
0.21
/V₁==
= 0.21 m²/91.
1256
23
A=Id': (6) = 12.56 m²
VS-Vu-Jegh
= 0.016-√2+70×5
FJ= POV, (1-cosq:)
= 83.64
=(1) (0.21) 183.64)(1)
= 17.56
= 0.02 m/sec
= 0.016 m/s.
Transcribed Image Text:Calculation time = 28, Volume = 5, mass: 70, h = 5. __ VOL 5 1=0.17 m²/sec (V₁ = = 0.17 time 28 12.56 A = I ² = = ~(4) = 12.56 m² / V5= Vn -√2gh = 0.013-√2016) =83.64 FJ=9Q VJ (1-cose) =(1/(0-17) (83.64) (1-C0545) = 4.265 90-45, time = 32, Volume = 5, mass=140 /V₁= Q = Vol = 5= 0.15 m²/sie tim 32 ..15 12.56 A=Id=-(6)=12.56² / V5= Vn -√2gh =0.011-√√2x 140.50 = 118.3 FJ=A@v₂ (1-cosys) =(1)(0.15) (118.3) (0.31 = 5.323 J 0=45 = 0.013 mhu h: 50mm = 0.011 m/s.c Calculation D 0=9 time=19, mass: 1oo, ho 50mm, Volume 5 Vol 50.26 m²/see time 19 / Vni V₁ = @= 0.26 12.56 A= d² = (16) = 12.56 m² / V5= V₁-√2gh =0.02-√2x100 50 = 100 FJ=PQV₂ (1-C059) =(1) (0-26) (100) (1-0) = 26 90-9: time = 23, mass = 70, h = 50mm, Volum. 5 VOL 5 0.21 /V₁== = 0.21 m²/91. 1256 23 A=Id': (6) = 12.56 m² VS-Vu-Jegh = 0.016-√2+70×5 FJ= POV, (1-cosq:) = 83.64 =(1) (0.21) 183.64)(1) = 17.56 = 0.02 m/sec = 0.016 m/s.
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