6.48 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Using equations from the numbered list below, determine AH for on. At IO C(diamond) C(graphite) - (1) C(diamond) + O2(g) → CO,(g) AH = -395.4 kJ (2) 2CO3(g) (3) C(graphite) + 0,(8) (4) 2CO(g) 2C0(g) + O2(8) AH = 566.0 kJ %3D CO(g) AH = -393.5 kJ > %3D C(graphite) + CO-(g) AH = -172.5 kJ >

6.48 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Using equations from the numbered list below, determine AH for on. At IO C(diamond) C(graphite) - (1) C(diamond) + O2(g) → CO,(g) AH = -395.4 kJ (2) 2CO3(g) (3) C(graphite) + 0,(8) (4) 2CO(g) 2C0(g) + O2(8) AH = 566.0 kJ %3D CO(g) AH = -393.5 kJ > %3D C(graphite) + CO-(g) AH = -172.5 kJ >

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter7: Chemical Energy

Section: Chapter Questions

Problem 5RQ

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