6.76 Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Using equations from the list below, determine AH for (2 C(graphite) CO2(g) C(diamond) 6. > AH = -395.4 kJ (1) C(diamond) + O2(8) (2) 2CO2(8) (3) C(graphite) + O2(g) (4) 2CO(g) 2CO(g) + O2(g) ΔΗ= 566.0 kJ → CO2(g) C(graphite) + CO2(g) AH= -172.5 kJ AH = –393.5 kJ Standard Enthalpies of Reaction (AHn) (Sample Problems 6.10 and 6.11) Concept Review Questions 6.77 What is the difference between the standard enthalpy of for- mation and the standard enthalpy of reaction? 6.78 How are AH? values used to calculate AHn? 6.79 Make any changes needed in each of the following equations so that the enthalpy change is equal to AH¡ for the compound: (a) Cl(g) + Na(s) (b) Н.О() - (c) N2(8) + H2(g) · NaCl(s) 2H(g) +02(8) NH3(8) > Skill-Building Exercises (grouped in similar pairs) 6.80 Use Table 6.3 or Appendix B to write a balanced formation equation at standard conditions for each of the following com- pounds: (a) CaCl2; (b) NaHCO;; (c) CCI4; (d) HNO3. 6.81 Use Table 6.3 or Appendix B to write a balanced formation equation at standard conditions for each of the following com- pounds: (a) HI; (b) SiF4; (c) O3; (d) Ca3(PO4)2- 6.82 Calculate AHn for each of the following: (a) 2H2S(g) + 30,(g) · (b) CH4(g) + Cl2(g) - 2SO2(g) + 2H2O(g) CCL,(1) + HCI(g) [unbalanced] Talauloto A H° for each of the following:
6.76 Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite so slowly that the enthalpy change of the process must be obtained indirectly. Using equations from the list below, determine AH for (2 C(graphite) CO2(g) C(diamond) 6. > AH = -395.4 kJ (1) C(diamond) + O2(8) (2) 2CO2(8) (3) C(graphite) + O2(g) (4) 2CO(g) 2CO(g) + O2(g) ΔΗ= 566.0 kJ → CO2(g) C(graphite) + CO2(g) AH= -172.5 kJ AH = –393.5 kJ Standard Enthalpies of Reaction (AHn) (Sample Problems 6.10 and 6.11) Concept Review Questions 6.77 What is the difference between the standard enthalpy of for- mation and the standard enthalpy of reaction? 6.78 How are AH? values used to calculate AHn? 6.79 Make any changes needed in each of the following equations so that the enthalpy change is equal to AH¡ for the compound: (a) Cl(g) + Na(s) (b) Н.О() - (c) N2(8) + H2(g) · NaCl(s) 2H(g) +02(8) NH3(8) > Skill-Building Exercises (grouped in similar pairs) 6.80 Use Table 6.3 or Appendix B to write a balanced formation equation at standard conditions for each of the following com- pounds: (a) CaCl2; (b) NaHCO;; (c) CCI4; (d) HNO3. 6.81 Use Table 6.3 or Appendix B to write a balanced formation equation at standard conditions for each of the following com- pounds: (a) HI; (b) SiF4; (c) O3; (d) Ca3(PO4)2- 6.82 Calculate AHn for each of the following: (a) 2H2S(g) + 30,(g) · (b) CH4(g) + Cl2(g) - 2SO2(g) + 2H2O(g) CCL,(1) + HCI(g) [unbalanced] Talauloto A H° for each of the following:
General Chemistry - Standalone book (MindTap Course List)
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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.147QP: The head of a strike anywhere match contains tetraphosphorus trisulfide, P4S3. In an experiment, a...
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78 please
![6.76 Diamond and graphite are two crystalline forms of carbon.
At 1 atm and 25°C, diamond changes to graphite so slowly that
the enthalpy change of the process must be obtained indirectly.
Using equations from the list below, determine AH for
(2)
Ce
C(graphite)
CO2(8)
C(diamond)
6.
AH = -395.4 kJ
h
(1) C(diamond) + O2(8)
(2) 2CO2(g)
(3) C(graphite) + O2(8)
(4) 2CO(g)
2CO(g) + O2(g)
AH = 566.0 kJ
It
fc
→ CO2(g)
C(graphite) + CO2(g) AH = –172.5 kJ
AH = -393.5 kJ
y
Standard Enthalpies of Reaction (AHn)
(Sample Problems 6.10 and 6.11)
Concept Review Questions
6.77 What is the difference between the standard enthalpy of for-
mation and the standard enthalpy of reaction?
6.78 How are AH values used to calculate AHn?
6.79 Make any changes needed in each of the following equations
so that the enthalpy change is equal to AH¡ for the compound:
(a) Cl(g) + Na(s)
(b) H2O(g)
(c) N2(g) + H,(8)
- NaCl(s)
2H(8) + 02(8)
NH3(8)
>
Skill-Building Exercises (grouped in similar pairs)
6.80 Use Table 6.3 or Appendix B to write a balanced formation
equation at standard conditions for each of the following com-
pounds: (a) CaCl2; (b) NaHCO3; (c) CCL4; (d) HNO3.
6.81 Use Table 6.3 or Appendix B to write a balanced formation
equation at standard conditions for each of the following com-
pounds: (a) HI; (b) SiF;; (c) O3; (d) Ca3(PO4)2.
6.82 Calculate AHn for each of the following:
(a) 2H2S(g) + 30(8) -
(b) CH,(8) + Cl2(8) -
2SO2(8) + 2H2O(g)
CCl,(1) + HCI(g)
>
[unbalanced]
Culauloto A H° for each of the following:](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3f1627aa-7129-483c-b690-510f18fd7049%2F2f394bb7-81c9-406e-9134-24a09d210145%2Feauoqw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6.76 Diamond and graphite are two crystalline forms of carbon.
At 1 atm and 25°C, diamond changes to graphite so slowly that
the enthalpy change of the process must be obtained indirectly.
Using equations from the list below, determine AH for
(2)
Ce
C(graphite)
CO2(8)
C(diamond)
6.
AH = -395.4 kJ
h
(1) C(diamond) + O2(8)
(2) 2CO2(g)
(3) C(graphite) + O2(8)
(4) 2CO(g)
2CO(g) + O2(g)
AH = 566.0 kJ
It
fc
→ CO2(g)
C(graphite) + CO2(g) AH = –172.5 kJ
AH = -393.5 kJ
y
Standard Enthalpies of Reaction (AHn)
(Sample Problems 6.10 and 6.11)
Concept Review Questions
6.77 What is the difference between the standard enthalpy of for-
mation and the standard enthalpy of reaction?
6.78 How are AH values used to calculate AHn?
6.79 Make any changes needed in each of the following equations
so that the enthalpy change is equal to AH¡ for the compound:
(a) Cl(g) + Na(s)
(b) H2O(g)
(c) N2(g) + H,(8)
- NaCl(s)
2H(8) + 02(8)
NH3(8)
>
Skill-Building Exercises (grouped in similar pairs)
6.80 Use Table 6.3 or Appendix B to write a balanced formation
equation at standard conditions for each of the following com-
pounds: (a) CaCl2; (b) NaHCO3; (c) CCL4; (d) HNO3.
6.81 Use Table 6.3 or Appendix B to write a balanced formation
equation at standard conditions for each of the following com-
pounds: (a) HI; (b) SiF;; (c) O3; (d) Ca3(PO4)2.
6.82 Calculate AHn for each of the following:
(a) 2H2S(g) + 30(8) -
(b) CH,(8) + Cl2(8) -
2SO2(8) + 2H2O(g)
CCl,(1) + HCI(g)
>
[unbalanced]
Culauloto A H° for each of the following:
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