60.0 cg = __________ g 3.09 dg = __________ cg 0.001 s = __________ ms 25 Ms = __________ s 0.0692 ks = __________ ms 4404.2 mol = __________ kmol 12 mol = __________ mmol 2 nmol = __________ μmol
60.0 cg = __________ g 3.09 dg = __________ cg 0.001 s = __________ ms 25 Ms = __________ s 0.0692 ks = __________ ms 4404.2 mol = __________ kmol 12 mol = __________ mmol 2 nmol = __________ μmol
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter1: Introduction To Chemistry
Section: Chapter Questions
Problem 1.72QE
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Question
- Complete the following chart. Use conversions as I have shown you, and show your work.
140 km = 140,000 m
2.65 m = 0.00265 km
0.0007 m = 0.7 mm
62.4 kg = 62,4000 g
60.0 cg = __________ g
3.09 dg = __________ cg
0.001 s = __________ ms
25 Ms = __________ s
0.0692 ks = __________ ms
4404.2 mol = __________ kmol
12 mol = __________ mmol
2 nmol = __________ μmol
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