(69,85) A 25g ice cube (pure water) at is placed into a 115g sample of pure water at 25 C. The information for water is given below. Determine the final temperature, in °C, of the water. You must consider all applicable cooling/heating/phase change steps for both the ice cube and the water. Cs (solid) = 2.1 J ¬K¬1 Cs (liquid) = 4.2 Jg-K-1 AHfus = 6.0 kJ mol-1
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- What is the total heat of reaction of the decomposition of C3H8 at 693.15 K. The reaction is 0.69 conversion of C3H8. Express answer in kJ per mol C3H8 decomposed.Use the molar DHf° under the formulas to calculate DH°rxn for the equations as balanced: 1. 2B2H6(g) + 3CO2(g) --> 2B2O3(s) + 3CH4(g) ΔH°rxn = _______ kJ ΔH°f = +36 –394 –1274 –75 kJ/mol exo ? endo_thermic 2. 2P2O5 + 2CaC2 -->P4 + 2CaCO3 + 2CO2 ΔH°rxn = _______ kJ ΔH°f = –1505 –59 ___ –1207 –394 kJ/mol exo ? endo_thermic 3. 2Na2CrO4(s) + 10HCl(g) --> 4NaCl(s) + 3Cl2(g) + Cr2O3(s) + 5H2O(l) ΔH°f = –1342 –92 –411 ___ –1140 –286 kJ/mol ΔH°rxn = _______ kJ exo ? endo_thermicWhen solid ammonium nitrate (NH4NO3) dissolves in water, the process is endothermic, with ΔHsolution = +25.69 kJ/mol . (This reaction has been used in commercial cold packs.)If 5.60 g NH4NO3 is dissolved in 100.0 g of water at 22.0° C, what is the final temperature of the solution? The total mass of the solution is 105.6 g (100.0 g H2O + 5.60 g NH4NO3 = 105.6 g) and the specific heat capacity of the solution is 4.18 J/(g·K). A) 0.0° C B) 17.9° C) 11.6° C D) –54.8° C E) 26.1° C
- As some of you know, I am an aficionado of Starbuck's Steamed Milk, Venti size. Steamed milk is made by passing superheated steam into a stainless steel container containing the milk. Assume that the stcam is at 25C,L-$40 calories/gram, and the specific heat of steam is 0.500 calories/gram/degree C. Also assume that the milk is at 5°C and that 750 ml of milk represent the Venti size. The stainless steel container can be considered to have a mass of 400. grams and a specific heal capacity of 0.600 Jgram/K. If the density of milk is its specific heat is 4.184 Vgram/K, how many grams of steam does it take to raise the milk's temperature to a comfortable 65 C? Thank you for your help!For the equilibrium system: H2O(g) + CO(g) <--> H2(g) + CO2(g). Delta heat of rxn: -42 kJ/mol and Kc=0.62 at 1260 K.0.10 mol each of water, CO, and CO2 (all at 1260 K) are placed in a sealed 1.0-Liter thermally-insulated vessel, which is also at 1260 K. When the system comes to equilibrium, which is true?-The temp & mass of CO would increase.-The temp & mass of CO would decrease.-The temp would remain constant & the mass of CO would increase.-The temp would increase and the mass of CO would decrease.-The temp would decrease and the mass of CO would increase.Give both answer plz A) The balanced combustion reaction for C6H6 is 2C6H6(l)+15O2(g)⟶12CO2(g)+6H2O(l)+6542 kJ If 6.900 g C6H6 is burned and the heat produced from the burning is added to 5691 g of water at 21 ∘ C, what is the final temperature of the water? B) Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.30 MJ1.30 MJ of energy in the form of heat if the temperature of the sodium is not to increase by more than 10.0 °C?10.0 °C? Use ?P=30.8 J/(K⋅mol)CP=30.8 J/(K⋅mol) for Na(l)Na(l) at 500 K
- A slow heat release pack is to be marketed based on mixing an anhydrous solid with just enough water to form one of its solid hydrates. Which will yield more heat, CaCl2 to CaCl2.6H2O or Na2SO4 to Na2SO4.10H2O? Assume that the same molar quantities of the anhydrous solid are used. You will have to look up the values of ∆H f,m . Sources must be cited appropriately with googleMrs S has severe urticaria. The prescriber has requested 500g of 2% w/w calamine in aqueous cream. You have 5% w/w calamine in aqueous cream in stock. You decide to prepare this product by extemporaneous dilution using aqueous cream as the diluent. How many grams of 5% w/w calamine in aqueous cream is needed to make 500g of 2% w/w calamine in aqueous cream? units – gAnswer the following the questions given below Given (Dissolution of Sodium Hydroxide) Mass of Water = 200g Initial Temperature of water = 20.0°C Final Temperature of water = 26.49 °C ?water= 5430.832J ?dissolution= 5566.6028J Mass of Solid NaOH= 5.0g Moles of solid NaOH=0.12501 mol Δ?of NaOH dissolution= -44.51 kJ/mol Questions: 1.Is the dissolution of NaOH endothermic or exothermic? Justify your answer. 2.If you touch the sides of a beaker containing NaOH being dissolved, will it feel warm or cold to touch?
- The DHvap of ethanol is 33.9 kJ/mol and its boiling point is 78.3 °C. Calculate the DSvap in J/K of 3.00 moles of ethanol. Write the correct equation that is used, and plugging in the correct numbers with the correct units.At constant pressure and 25°C, what is ΔH° for the following reaction2C2H6(g) + 7O2(g) → 4CO2(g) + H2O(l)if the complete consumption of 38.2 g of C2H6 liberates 1981 kJ of heat energy?a. 3120 kJb. 1560 kJc. 5030 kJd. 2510 kJe. 784.05 kJShow complete solution to get complete credit score. Observe organized calculation format. (Given, Required, Solution) The industrial method currently used to produce butanol is the hydration of butene. C4H8(g) + H2O(g) → C4H10O(g) The enthalpy values for the following reactions are: 4C(s) + 4H2(g) → C4H8(g) ΔH = – 7·1 kJ mol–1 4C(s) + 5H2(g) + ½O2(g) → C4H10O(g) ΔH = – 292·8 kJ mol–1 2H2(g) + O2(g) → 2H2O(g) ΔH = – 483·6 kJ mol–1 Using the data above, calculate the enthalpy change, in kJ mol–1, to produce butanol by hydration of butene.