- (6)lf the heat of combustion for a mole of methane (CHA) is -2,200 kJ, how many grams of methane must be burned to heat 455 g of ice at 0°C to water at 88°C?

Physical Chemistry
2nd Edition
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Ball, David W. (david Warren), BAER, Tomas
Chapter2: The First Law Of Thermodynamics
Section: Chapter Questions
Problem 2.79E: The enthalpy of combustion of diamond is -395.4 kJ/mol. C s, dia O2 g CO2 g Determine the fH of C...
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• (6)lf the heat of combustion for a mole of methane (CH) is -2,200 kJ, how
many grams of methane must be burned to heat 455 g of ice at 0°C to water
at 88°C?
Transcribed Image Text:• (6)lf the heat of combustion for a mole of methane (CH) is -2,200 kJ, how many grams of methane must be burned to heat 455 g of ice at 0°C to water at 88°C?
Expert Solution
Step 1: Given information is

Given that,

Mass of ice = 455g

Initial temperature of ice = 0°C

Final temperature of water = 88°C

Heat evolved from combustion of 1 mole of methane = -2200 kJ.

Specific heat of water = 4.2 kJ/mole.°C

Latent heat of melting = 334 J/g

Latent heat of melting is the amount of heat required to melt one gram of ice at 0°C to water at 0°C.

There are two phases of heat involved in conversion of ice at 0°C to 88°C.

  • First conversion of ice at 0°C to water at 0°C.
  • Second heating of water at 0°C to 88°C.
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