7. In aqueous solution, hydrazine is a base that can accept two protons:N2H4(aq) + H2O(1) 2N¿H5*(aq) + OH(aq)Кы= 8.5 x 10-7N2H5* (aq) + H2O(1) ZN¿H²*(aq) +OH(aq)Kb2 = 8.9 x 10-16What is the pH of a 0.010 mol.L-' hydrazine solution?b. What is the concentration of N2H4, N2H5*, and N2H6²+ at equilibrium?а.

#7 (a): Since Kb2 << Kb1, the OH-(aq) contribution is mainly due to the 1st hydrolysis…

7. In aqueous solution, hydrazine is a base that can accept two protons: N2H4(aq) + H2O(1) 2N¿H5*(aq)+ OH(aq) Kb1 = 8.5 x 10-7 %3D N2H5* (aq) + H2O(1) 2N¿H¿²*(aq) +OH(aq) Kb2 = 8.9 x 10-16 %3D What is the pH of a 0.010 mol.L·' hydrazine solution? b. What is the concentration of N2H4, N2H5*, and N2H6²* at equilibrium? а.

7. In aqueous solution, hydrazine is a base that can accept two protons: N2H4(aq) + H2O(1) 2N¿H5(aq)+ OH(aq) Kb1 = 8.5 x 10-7 %3D N2H5 (aq) + H2O(1) 2N¿H¿²(aq) +OH(aq) Kb2 = 8.9 x 10-16 %3D What is the pH of a 0.010 mol.L·' hydrazine solution? b. What is the concentration of N2H4, N2H5, and N2H6²* at equilibrium? а.

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

ChapterL2: Mass Spectrometry

Section: Chapter Questions

Problem 5CTQ

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