If a question has a formula given, please use the one provided.Give me detail and proper solution. 7. The financial aid director of a college believes that at least 30%of the students are receiving some sort of financial aid. To seewhether his belief is correct, the director selects a sample of 60students and finds that 15 are receiving financial aid. At a = 0.05.can the director conclude that at least 30% of the students arereceiving financial aid? Construct a corresponding confidenceinterval for the population parameter. (0₁ p+ 2.95 √ F(-p)n

Given Population proportion p=0.30, n=sample size=60, n=sample size=60, x=15, level of significance…

Answered: 7. The financial aid director of a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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(c) An epidemiologist is worried about the ever increasing trend of malaria in a certain locality and wants to estimate the proportion of people infected in the peak malaria transmission period. If he takes a random sample of 150 people in that locality during the peak transmission period and finds that 60 of them are positive for malaria, find i. 99% confidence interval for the proportion of the whole infected people in that locality during the peak malaria transmission period.
11. a. The manufacturers are interested in estimating the percentage of defective light bulbscoming from a certain process. They want a 90% confidence interval with a margin of error of 2%. How many light bulbs must they test?Choices:(a) 50 (b) 500 (c) 800 (d) 2000 (e) 300011. b. Same question as in the previous problem, but assume they had a reason to believe the proportion is fairly close to 6%. How large a sample must they test?Choices:(a) 50 (b) 500 (c) 800 (d) 2000 (e) 3000
1. A pollster wants to conduct a pre-election poll with a margin of error of 3.5% and a 95% confidence level. The pollster does not know ahead of time what the proportion in favor of either candidate is. How many people must be included in the sample to achieve the goal of a 3.5% margin of error? [Note that p -hat is unknown and is therefore assumed to be 0.5.] 2. In another pre-election poll, a pollster finds that 438 out of 600 people polled favor, Smith. Construct the 95% confidence interval for the proportion (to nearest 0.001) of people in the whole population who favor Smith.
(a)A random sample of 25 college males was obtained and each was asked to report their actual height and what they wished as their ideal height. A 95% confidence interval for µd = average difference between their ideal and actual heights was 0.8" to 2.2". Based on this interval, which one of the null hypotheses below (versus a two-sided alternative) can be rejected? all the above c. H0: µd = 1.5 H0: µd = 0.5 b. H0: µd = 1.0 H0: µd = 2.0 (b)Which of the following is a correct form of an alternate hypothesis for paired data? H1: μd = p H1: μ1 ≠ μ2 H1: μd > 0 H1: μ1 = μ2 (C)Which of the following is always the null hypothesis for two sample proportions? d. H0: p1 = 3 H0: p1 < μ2 H0: p1 ≠ p2 H0: p1 = p2
3. In a random sample of 300 persons eating lunch at a Lexington pizzeria, 270 ordered pizza. a) Find and interpret a 95% confidence interval for the true proportion of people who eat pizza at this Lexington pizzeria? b) If we take 270/300 = 0.90 as an estimate of the corresponding true proportion, with what confidence can we assert that our error is less than 0.04?
Suppose that the researchers wish to use a maximum error of 0.05 at the 90% confidence level, what is the minimum number of homes (round up to the nearest whole number) that they need to visit? Formula: E=zα/2√p¯(1−p¯)/n Hint: Isolate n on one side using algebra. Confidence Level 1−α Significance Level α α/2 zα/2 90% = 0.90 0.10 0.05 1.645 95% = 0.95 0.05 0.025 1.96 98% = 0.98 0.02 0.01 2.33 99% = 0.99 0.01 0.005 2.576
A researcher administers a treatment to a sample from a population with a mean of m=50. If the treatment is expected to increase scores and a one-tailed test is used to evaluate the treatment effect, the the null hypothesis states that m=40. True or false?
Suppose that you intend to find a 95% confidence interval for a population mean by applying the one-mean z-interval procedure to a sample of size 100. a. What would happen to the accuracy of the estimate if you used a sample of size 50 instead but kept the same confidence level of 0.95?b. What would happen to the accuracy of the estimate if you changed the confidence level to 0.90 but kept the same sample size of 100?
(d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed? A. Yes, the population does not need to be normally distributed. B. Yes, the population needs to be normally distributed. C. No, the population does not need to be normally distributed. D. No, the population needs to be normally distributed.
Suppose a new production method will be implemented if a hypothesis test supports the conclusion that the new method reduces the mean operating cost per hour. #1 State the appropriate null and alternative hypotheses if the mean cost for the current production method is $280 per hour. A) H0: ? ≤ 280 Ha: ? > 280 B) H0: ? = 280 Ha: ? ≠ 280 C) H0: ? < 280 Ha: ? ≥ 280 D) H0: ? > 280 Ha: ? ≤ 280 E) H0: ? ≥ 280 Ha: ? < 280 #2 What is the type I error in this situation? What are the consequences of making this error? A) It would be claiming ? ≤ 280 when the new method does not lower costs. This mistake could result in implementing the method when it would not lower costs. B)It would be claiming ? < 280 when the new method does not lower costs. This mistake could result in implementing the method when it would not lower costs. C) It would be claiming ? ≥ 280 when the method really would lower costs. This mistake could result in not implementing a method…
In a test of H0: µ=27 against HA: µ ≠ 27, using α=.05, you get a 95% confidence interval with a lower limit of 26.7 and an upper limit of 28.3. What is your conclusion? a. fail to reject the null hypothesis. b. reject the null hypothesis. c.no enough information

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