Homework Help is Here – Start Your Trial Now!
Science
Chemistry
8 Add the half reactions together, cancel out any species that occur on both sides of the equation, and double-check for balanced atoms and charge. 2Cr(OH)3 + 10 OH + 3C1O + 3H₂O + 6e* → 2CrO4²- + 8H₂O + 6e + 3Cl +60H* The simplified equation becomes: ► 2Cr(OH)3 + 4OH + 3C1O → 2CrO4²- + 5H₂O + 3C1- This is balanced for all atoms and with respect to charge.

8 Add the half reactions together, cancel out any species that occur on both sides of the equation, and double-check for balanced atoms and charge. 2Cr(OH)3 + 10 OH + 3C1O + 3H₂O + 6e* → 2CrO4²- + 8H₂O + 6e + 3Cl +60H* The simplified equation becomes: ► 2Cr(OH)3 + 4OH + 3C1O → 2CrO4²- + 5H₂O + 3C1- This is balanced for all atoms and with respect to charge.

General Chemistry - Standalone book (MindTap Course List)
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter19: Electrochemistry
Section: Chapter Questions
Problem 19.140QP
See similar textbooks
icon
Related questions
Question
100%
Demonstrate that step 8 of the example in basic solution is balanced with respect to both mass and charge. That is, for mass balance, show that the number of each type of atom is the same on the reactant and product side, and for charge balance, show that the total charge of all species is the same on the reactant and product side.
8 Add the half reactions together, cancel out any species that occur on both sides of the equation, and double-check for balanced atoms and charge. 2Cr(OH)3 + 10 OH + 3C1O+ 3H₂O + 6e* → 2CrO4²- + 8H₂O + 6e + 3Cl + 60H* The simplified equation becomes: ► 2Cr(OH)3 + 4OH + 3C10 ➜ 2CrO4²- + 5H₂O + 3C1- This is balanced for all atoms and with respect to charge.
Transcribed Image Text:8 Add the half reactions together, cancel out any species that occur on both sides of the equation, and double-check for balanced atoms and charge. 2Cr(OH)3 + 10 OH + 3C1O+ 3H₂O + 6e* → 2CrO4²- + 8H₂O + 6e + 3Cl + 60H* The simplified equation becomes: ► 2Cr(OH)3 + 4OH + 3C10 ➜ 2CrO4²- + 5H₂O + 3C1- This is balanced for all atoms and with respect to charge.
Expert Solution
steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Electrochemical Cells
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
General Chemistry - Standalone book (MindTap Cour…
General Chemistry - Standalone book (MindTap Cour…
Chemistry
ISBN:
9781305580343
Author:
Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:
Cengage Learning
Chemistry: Principles and Practice
Chemistry: Principles and Practice
Chemistry
ISBN:
9780534420123
Author:
Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781133611097
Author:
Steven S. Zumdahl
Publisher:
Cengage Learning
Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:
9781938168390
Author:
Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:
OpenStax
SEE MORE TEXTBOOKS