8.521 grams of precious metals, M (atomic weight 107.87 g/mol) is to be isolated from 15.78% metal nitrate solution (m:m) by electroplating. What volume (mL) solution is necessary for the electroplating experiment in order to isolate 8.521 grams of M? Assume a density of the solution of 1.274 g/ml and a molar mass of, MNO3 = 169.87 g/mol). Round off your answer to the correct number of significant figures but do not write the mL unit.

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