891, 937, 959, 1017, 1047, 1097, 1169, 1173, 1184, 1235, 1266, 1345, 1353, 1357, 1391, 1414, 1453, 1524, 1557, 1581, 1583, 1590, 1658, 1685, 1690, 1734, 1744, 1765, 1776, 1783, 1783, 1790, 1797, 1849, 1862, 1888, 1894, 1895, 1901, 1906, 1928, 1941, 1949, 1952, 1960, 2022, 2037, 2048, 2052, 2058, 2067, 2103, 2109, 2113, 2163, 2178, 2240, 2245, 2269, 2288, 2452, 2651, 2668, 2886, 2921, 3045, 3276, 3356, 3439, 3749, 4387, 4437, 4578, 4899, 5000, 5290, 5404, 5867, 6128, 6666, 7103, 7757, 7999, 8019, 8773, 9296, 9475, 9595, 9838, 10016create a table of frequency using this formula. show your solution 3210:51 PM O ARoexanne JovenirAD XF xANx UNDr xa MC xX Cax xUNx2/SECONDSEMESTER/STATS/OANNOATED patO Add textV OrawY Hig+ 2 E Page view A Read aloudIn the class 12-18, 12 is called the lower limit of the class, and 18 is called the upper limit ofthe class.Steps in Constructing a Quantitative Frequency Distribution TableStep 1: Determine the range of the data. The range, R, is the difference between the highestvalue and the smallest value in a set of data.Range = Highest Value - Lowest ValueStep 2: Determine the minimum number of classes denoted by k. This is obtained by solvingthe square root of the total number of frequency (N) in a set of data. The minimum number ofclasses should be rounded up to the nearest whole number.k = VNStep 3: Determine the class size denoted by c. This is obtained by solving the quotient of therange of the set of data and the minimum number of classes. Note that the class size shouldhave the same number of decimal places as the raw data.RStep 4: Enumerate the classes. Use the lowest value as the first lower limit. Take note of theclass size as you create the other classes.Step 5: Determine the frequency for each class.O 33°C Haze A 6noF11F12Aprt scInsor7.YP.H.K...EditMore

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Frequency distribution table :
A distribution table could be a graphic that presents values and…