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- 6. A sample of an alum was analysed by atomic spectroscopy and gravimetrically to determine its structure. A 0.1000 g of the sample when treated with BaCl₂ produced 0.0984 g of a white solid after drying to constant weight. Another 0.1000 g sample of the alum when heated at 105°C for several hours produced a weight loss of 0.04558 g while the % of K in the sample was determined by atomic spectroscopy to be 8.240%. Use these results to work out a formula for the alum. [M,/ g mole¹: K 39.10; Al 26.98; BaSO, 233.39; SO² 96.06; H₂O 18.0148]Mesityl oxide( (CH3)2C=CHCOCH3) shows two bands at 230 nm (12600) and 327 nm (98). But its isomer, ( CH2=C(CH)3-CH2COCH3) does not show any bands above 210 nm. Explain.) Calculate the ΔG°rxn using the following information. 4 HNO3(g) + 5 N2H4(l) → 7 N2(g) + 12 H2O(l) ΔG°rxn = ? ΔG°f (kJ/mol) -73.5 149.3 -237.1
- Noncontact AFM images for the HBC, or Hexa-peri-hexabenzocoronene molecule. (a) Stick model. (b) Constant-height AFM measurements for an HBC molecule on a Cu (111) surface substrate. (c) A pseudo-three-dimensional representation that highlights the local maxima. (d) Calculated electron density above the molecular plane. From Gross et al. [15 Links to an external site.]. Based on the AFM image shown in (b), what kind of substance is Hexa-peri-hexabenzocoronene? There may be more than one correct answer.As part of an investigation on Pb in biological ecosystems, some grasses that grew along the road and were exposed to emissions from motor gasoline were collected. 6.2501 g of grass were calcined to destroy all organic matter, the inorganic residue was properly treated and finally made up to 100 mL. An aliquot of 50 mL of this solution was read in an atomic absorption spectrophotometer registering an absorbance of 0.1250; then 0.10 mL of a standard solution of 55 µg of Pb / mL were added to the other 50 mL, with this fortified sample, another absorbance measurement was made, which was 0.1798. Calculate the µg of Pb / g of grassThe maximum safe [Ba2+]=1.5x10-5M. Maintaining 1.0x10-3M levels for each of the anions below would ensure that this level is achieved except (Ksp of BaF2=1.7x10-6, BaCO3=5.9x10-9, BaC2O4=7.4x10-14, and BaSO4=1.1x10-10) A SO42- B C2O42+ C CO32- D F-
- Please help me fill the remaining spaces. The spaces marked with NA don't need to be calculate. Name Molecular Weight Amounts used mmol Equivalents M.P or BP (C) Density (g/mL) Indene 116.16 .5mL MP=-2 BP=181-182 .996 Borane-tetrahydrofuran Complex 85.94 2.8mL 1 MP= -108 BP=66 NA 30% Hydrogen Peroxide 34.01 1mL MP= -33 BP=108 NA 3 M NaOH(aq) 40 .7mL MP=318 BP=1390 NA Diethyl Ether 74.12 NA NA NA BP=75-78 .902 Hexanes 86.17 NA NA NA BP=65.5-68.3 .659 Potassium Permanganate 158.03 NA NA NA BP=100 1.0 1-Indanol (Product) 134.13 NA MP=50-54 NA 2-Indanol (Product) Same as Above Same as Above Same as Above NA MP=68-71 NAWeight of crude/pure product: 0.819/0.047g Percent yield: Theoretical Yield: Melting Point crude/pure:195/190 Q: What would the theoretical yield froms the Diels-Alder Adduct with your product. Also, what is the actual yield? How do i calculate those? i used anthracene 200mg, maleic anhydride 110 mg and 6ml of xyleneINORGANIC Chemistry Starting product was [(Me5dien)CoCl2] and reacted with NaSCN to produce [(Me5dien)Co(SCN)2] Using the graphs attached, the IR data tells you that the binding mode is N coordination. How does the IR data agree (or disagree) with the peak shifts (Uv-Vis spect) IR Product 1, [(Me5dien)CoCl2] 29041.04, 2812.76, 2761.62 cm-1 (carbon bond) 1457.35 cm-1 (CH2) 1263.91 cm-1 (possibly C-N stretch) Product 2, [(Me5dien)Co(SCN)2] 2968.54-2870.67 cm-1 (C-C) 2059.41 cm-1 (N=C=S) 1470.28 cm-1 (CH2) Uv-vis [(Me5dien)CoCl2] Peak A: 531.8 nm, 0.722 Abs Peak B: 609.7 nm, 0.666 Abs [(Me5dien)Co(SCN)2] Peak A: 510.20 nm, 0.357 Abs Peak B: 608.20 nm, 0.401 Abs
- The two square-planar isomers of [PtBrCl(PR3)2] (where PR3 is a trialkylphosphene) have different 31P-NMR spectra as shown below. For this exercise, we ignore the coupling to 195Pt (I=1/2 at 33% abundance). One isomer (A) shows a single 31P resonance; the other (B) shows two 31P resonances, each of which is split into a doublet by the second 31P nucleus. Which isomer is cis and which is trans? Draw the structures of the two isomers.Explain in detail Remote Spectroscopy via NIRWhat is the molecular mass observed for Man9(GlcNAc)2 if it has a mass spectrometry ionization that imparts a +3 charge state? .
