90.0 V i a) Find the equivalent capacitance (in µF) of the system. HF

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
Problem 43P
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Consider the circuit shown in the figure, with C₁ = 5.92 μF and C₂ = 7.54 μF.
2.00 µF
6.00 uF
+
90.0 V
HE
C₂
i
(a) Find the equivalent capacitance (in µF) of the system.
μF
(b) Find the charge (in µC) on each capacitor.
5.92 μF capacitor
6.00 μF capacitor
7.54 µF capacitor
2.00 μF capacitor
μC
μC
μC
μC
(c) Find the potential difference (in V) on each capacitor.
5.92 µF capacitor
V
6.00 μF capacitor
V
7.54 μF capacitor
V
2.00 μF capacitor
V
(d) Find the total energy (in mJ) stored by the group.
mJ
Transcribed Image Text:Consider the circuit shown in the figure, with C₁ = 5.92 μF and C₂ = 7.54 μF. 2.00 µF 6.00 uF + 90.0 V HE C₂ i (a) Find the equivalent capacitance (in µF) of the system. μF (b) Find the charge (in µC) on each capacitor. 5.92 μF capacitor 6.00 μF capacitor 7.54 µF capacitor 2.00 μF capacitor μC μC μC μC (c) Find the potential difference (in V) on each capacitor. 5.92 µF capacitor V 6.00 μF capacitor V 7.54 μF capacitor V 2.00 μF capacitor V (d) Find the total energy (in mJ) stored by the group. mJ
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