Question

Asked Jan 22, 2020

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*A 0.10 kg block suspended from a spring is pulled to 8.0 cm below its equilibrium position and released. When the block passes the equilibrium position, it has a speed of 0.40 m/s. What is the speed of the block when it is 4.0 cm from the equilibrium position?*

Step 1

The velocity of the block, when it crosses from the equilibrium position is,

The angular frequency of the Simple harmonic motion is,

Step 2

Substitute the equation (II) in equation (I).

Substitute the values,

Step 3

The speed of the block, when it is from the equilib...

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