Asked Jan 22, 2020

A 0.10 kg block suspended from a spring is pulled to 8.0 cm below its equilibrium position and released. When the block passes the equilibrium position, it has a speed of 0.40 m/s. What is the speed of the block when it is 4.0 cm from the equilibrium position?


Expert Answer

Step 1

The velocity of the block, when it crosses from the equilibrium position is,

The angular frequency of the Simple harmonic motion is,

Physics homework question answer, step 1, image 1
Step 2

Substitute the equation (II) in equation (I).

Substitute the values,

Physics homework question answer, step 2, image 1
Step 3

The speed of the block, when it is from the equilib...

Physics homework question answer, step 3, image 1

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Newtons Laws of Motion

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