A2 kg block is attached to a spring of force constant 500 N/m, as shown in the figure below. The block is pushed 10 cm to the left of equilibrium and is then released from rest. What is the speed of the block (in m/s) as it passes through equilibrium if the coefficient of friction between the block and the surface is 0.400? x= 0 Lütfen birini seçin: а. 1.3 b. 2.9 C. 4.5 d. 5.3 e. 7.9

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A: Given: Mass m=0.500 kg Elongation  y=10.5 cm=10.5×10-2 m Mass m1=1.25 kg

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A: Solution: Given that m = 1.6 kg h = 1.3 m k = 315 N/m

Q: 5) What is the distance the lower spring is extended from its unstretched length? cm Submit 6)…

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Spring Potential Energy

The potential energy is the energy possessed by a body by virtue of its position or the energy held by the object due to its position relative to other objects, its force like stresses, charge, and other factors affecting the particles of the body. The potential energy is the measure of the net work done by or on the body. The spring potential energy is the potential energy stored due to the deformation of an elastic spring and this elasticity is due to the stretched spring. The elasticity is the ability of a solid-state matter to come back to its equilibrium position or original position after any kind of external force is acted on it. It is also known as Elastic potential energy. The potential energy here is caused due to the displacement of the spring from its equilibrium position to another position and this potential energy is equal to the net work done due to the stretching of the spring. It also resembles the same mechanics of the oscillation of a simple pendulum, where due to the external force, the object moves from its equilibrium position to its maximum ends and the periodic motion continues till it comes back to the equilibrium position to rest.