A 0.478 g sample of an unknown strong base is dissolved in 50.0 mL of water and titrated with a 0.135 M HCL solution. The equivalence point is reached when a total of 29.0 mL of HCL is added. The base and acid conbine in a 1:1 ratio. (a) How many moles of base are neutralized when the equivalent point is reached? (b) What was the initial concentration (M) of this unknown base? (c) What is the molar mass of the unknown base?

Introduction to General, Organic and Biochemistry
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Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter8: Acids And Bases
Section: Chapter Questions
Problem 8.115P: 8-115 When a solution prepared by dissolving 0.125 g of an unknown diprotic acid in 25.0 mL of water...
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A 0.478 g sample of an unknown strong base is dissolved in 50.0 mL of water and titrated with a 0.135 M HCL solution. The equivalence point is reached when a total of 29.0 mL of HCL is added. The base and acid conbine in a 1:1 ratio.

(a) How many moles of base are neutralized when the equivalent point is reached?

(b) What was the initial concentration (M) of this unknown base?

(c) What is the molar mass of the unknown base?

Expert Solution
Step 1

When acid and base combine with each other then they form salt and water. The reaction is called Neutralization reaction, where acid and base neutralizes each other.

During neutralization reaction, equivalent of an acid become equal to equivalent of a base.

Formula used

N1V1 = N2V2

where N is normality of an acid/base.

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