A 0.520-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of11.8 cm. (Assume the position of the object is at the origin at t = 0.)(a) Calculate the maximum value of its speed.46.258cm/s(b) Calculate the maximum value of its acceleration.181.323cm/s(c) Calculate the value of its speed when the object is 9.80 cm from the equilibrium position.25.78cm/s(d) Calculate the value of its acceleration when the object is 9.80 cm from the equilibrium position.-150.74cm/s²(e) Calculate the time interval required for the object to move from x = 0 to x = 3.80 cm.Can you use your equation for x(t) to determine the time for the object to first reach 3.80 cm? s

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Description: A 0.520-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of11.8 cm. (Assume the position of the object is at the origin at t = 0.)(a) Calculate the maximum value of its speed.46.25

a) The equation of motion of the particle for this kind of motion: md2xdt2=-kxGeneral solution of…

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A 0.520-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of 11.8 cm. (Assume the position of the object is at the origin at t = 0.)

A 0.520-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of 11.8 cm. (Assume the position of the object is at the origin at t = 0.)

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter12: Oscillatory Motion

Section: Chapter Questions

Problem 13P: A 500-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic...

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