I need full answer with details. A 0.547 g sample of an unknown solute dissolved in 14.0 g of tert-butanol produces a solution with a freezing point of22.70 °C. What is the molar mass of the solute?For tert-butanol T = 25.50 °C, kf = 9.10 °C · kg · mol-.molar mass =g/mol

Answered: A 0.547 g sample of an unknown solute…

Principles of Modern Chemistry

8th Edition

ISBN:9781305079113

Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler

Chapter11: Solutions

Section: Chapter Questions

Problem 46P

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I need full answer with details.

A 0.547 g sample of an unknown solute dissolved in 14.0 g of tert-butanol produces a solution with a freezing point of
22.70 °C. What is the molar mass of the solute?
For tert-butanol T = 25.50 °C, kf = 9.10 °C · kg · mol-.
molar mass =
g/mol

Expert Solution

Step 1

Solution is made up of two components which are solute and solvent. Solute is present in the minor amount and solvent is present in the major amount. Here, tert-butanol is the solvent.

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