A 0.5657-g sample of a chlorocarbon compound was analyzed for its chloride content by burning it in oxygen and collecting the evolved gases in a solution of NaOH. After neutralizing, the sample was treated with 42.25 mL of a 0.2320 M AgNO3 solution. This precipitated the chloride (CI") out as AgCl and left an excess of AgNO3. The excess AgNO3 was titrated with 0.1326 M KSCN and required 18.47 mL to reach equivalence. Calculate the % w/w CI- (35.45 g/mol) in the sample. Provide your answer to two places after the decimal point and without units. Reactions: A9CI (s) Ag+ + SCN- → A9SCN (s) Ag+ + Cl

Fundamentals Of Analytical Chemistry
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Chapter13: Titrations In Analytical Chemistry
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Problem 13.20QAP
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A 0.5657-g sample of a chlorocarbon compound was analyzed for its chloride content by burning it in oxygen and collecting the evolved gases in a solution of NaOH. After
neutralizing, the sample was treated with 42.25 mL of a 0.2320 M AgNO3 solution. This precipitated the chloride (CI") out as AgCl and left an excess of AgNO3. The excess
AGNO3 was titrated with 0.1326 M KSCN and required 18.47 mL to reach equivalence.
Calculate the % w/w CI (35.45 g/mol) in the sample. Provide your answer to two places after the decimal point and without units.
Reactions:
→ AgCl (s)
→ AGSCN (s)
Ag+ + Cl-
Ag+ + SCN-
Transcribed Image Text:A 0.5657-g sample of a chlorocarbon compound was analyzed for its chloride content by burning it in oxygen and collecting the evolved gases in a solution of NaOH. After neutralizing, the sample was treated with 42.25 mL of a 0.2320 M AgNO3 solution. This precipitated the chloride (CI") out as AgCl and left an excess of AgNO3. The excess AGNO3 was titrated with 0.1326 M KSCN and required 18.47 mL to reach equivalence. Calculate the % w/w CI (35.45 g/mol) in the sample. Provide your answer to two places after the decimal point and without units. Reactions: → AgCl (s) → AGSCN (s) Ag+ + Cl- Ag+ + SCN-
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