A 1.00-cm-high object is placed 4.95 cm to the left of a converging lens of focal length 7.75 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. 8.83 position cm in front of the second lens v 2.21 Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm height

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter26: Image Formation By Mirrors And Lenses
Section: Chapter Questions
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Can you help me calculate the height. I kept getting it wrong.

A 1.00-cm-high object is placed 4.95 cm to the left of a converging lens of focal length 7.75 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and
height of the final image.
position
8.83
cm in front of the second lens v
2.21
height
Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm
Transcribed Image Text:A 1.00-cm-high object is placed 4.95 cm to the left of a converging lens of focal length 7.75 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position 8.83 cm in front of the second lens v 2.21 height Calculate the magnification produced by each lens. Then consider how the magnification relates image size and object size for each lens to find the height of the final image. cm
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