A 16.0-mm length of wire consists of 7.0 mm of copper followed by 9.0 mm of aluminum, both of diameter 1.4 mm. A voltage difference of 95 mV is placed across the composite wire. The resistivity of copper is 1.68×10−8Ω⋅m and the resistivity of aluminum is 2.65×10−8Ω⋅m
A 16.0-mm length of wire consists of 7.0 mm of copper followed by 9.0 mm of aluminum, both of diameter 1.4 mm. A voltage difference of 95 mV is placed across the composite wire. The resistivity of copper is 1.68×10−8Ω⋅m and the resistivity of aluminum is 2.65×10−8Ω⋅m
Chapter9: Current And Resistance
Section: Chapter Questions
Problem 28P: An aluminum wire 1.628 mm in diameter (14-gauge) carries a current of 3.00 amps, (a) What is the...
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A 16.0-mm length of wire consists of 7.0 mm of copper followed by 9.0 mm of aluminum, both of diameter 1.4 mm. A voltage difference of 95 mV is placed across the composite wire. The resistivity of copper is 1.68×10−8Ω⋅m and the resistivity of aluminum is 2.65×10−8Ω⋅m
What is the total resistance (sum) of the two wires?
Express your answer to two significant figures and include the appropriate units.
R total=
What is the current through the wire?
Express your answer to two significant figures and include the appropriate units.
I=
What is the voltage across the copper part?
Express your answer to two significant figures and include the appropriate units.
VCu=
What is the voltage across the aluminum part?
Express your answer to two significant figures and include the appropriate units.V
What is the voltage across the aluminum part?
Express your answer to two significant figures and include the appropriate units.
What is the voltage across the aluminum part?
Express your answer to two significant figures and include the appropriate units.
VAl=
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