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A 20.00 mL sample of vinegar was titrated to the end point with 31.70 mL of 0.15 M NAOH solution. Given that the molar mass of acetic acid = 60.1 g/mol, and the density of the vinegar solution is 1.10 g/mL, then the mass % of acetic acid in vinegar is equal to Select one: a. 1.3% b. 3.2% C. 2.1% d. 1.8% е. 1.5%

A 20.00 mL sample of vinegar was titrated to the end point with 31.70 mL of 0.15 M NAOH solution. Given that the molar mass of acetic acid = 60.1 g/mol, and the density of the vinegar solution is 1.10 g/mL, then the mass % of acetic acid in vinegar is equal to Select one: a. 1.3% b. 3.2% C. 2.1% d. 1.8% е. 1.5%

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 148QRT
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please solve chemistry 109 lab 

A 20.00 mL sample of vinegar was titrated to the end point with 31.70 mL of 0.15 M NaOH solution. Given that the molar mass of acetic acid = 60.1 g/mol, and the density of the vinegar solution is 1.10 g/mL, then the mass % of acetic acid in vinegar is equal to Select one: a. 1.3% b. 3.2% С. 2.1% d. 1.8% е. 1.5%
Transcribed Image Text:A 20.00 mL sample of vinegar was titrated to the end point with 31.70 mL of 0.15 M NaOH solution. Given that the molar mass of acetic acid = 60.1 g/mol, and the density of the vinegar solution is 1.10 g/mL, then the mass % of acetic acid in vinegar is equal to Select one: a. 1.3% b. 3.2% С. 2.1% d. 1.8% е. 1.5%
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