A 25.0 mL sample of a 0.100 M solution of acetic acid is titrated with a 0.125 M solution of NaOH. Calculate the pH of the titration mixture after 10.0, 20.0, and 30.0 mL of base have been added. The Ka for acetic acid is 1.76×10–5. pH after 10.0 mL base added = pH after 20.0 mL base added = pH after 30.0 mL base added =
A 25.0 mL sample of a 0.100 M solution of acetic acid is titrated with a 0.125 M solution of NaOH. Calculate the pH of the titration mixture after 10.0, 20.0, and 30.0 mL of base have been added. The Ka for acetic acid is 1.76×10–5. pH after 10.0 mL base added = pH after 20.0 mL base added = pH after 30.0 mL base added =
Chapter15: Acid-base Equilibria
Section: Chapter Questions
Problem 59E: Consider the titration of 100.0 mL of 0.200 M acetic acid (Ka = 1.8 105) by 0.100 M KOH. Calculate...
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A 25.0 mL sample of a 0.100 M solution of acetic acid is titrated with a 0.125 M solution of NaOH. Calculate the pH of the titration mixture after 10.0, 20.0, and 30.0 mL of base have been added. The Ka for acetic acid is 1.76×10–5.
pH after 10.0 mL base added =
pH after 20.0 mL base added =
pH after 30.0 mL base added =
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