Question

A 25kg block on the end of a spring is lifted upward to a point 2 m away from it’s equilibrum position and released from rest. As the block heads downward back towards its equilibrium position it first arrives at a point 0.6 m above the equilibrium position after a time 0.3 seconds had elapsed. What is the spring constant of the spring?

Step 1

Given mass of the block m = 25kg

Initial displacement of the block is 2 meters .

Initial velocity of the block is zero.

Motion of the block mentioned in the question will be simple harmonic motion.

For bodies in SHM motion, displacement as a function of time is as follows:

Step 2

We can find the values of A and phi as follows:

Step 3

After substituting A and phi values in equat...

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