the position of a mass hanging from a spring as it oscillates has the form x(t)=0.2cos(6.7t). (All quantities given are in standard units). If the mass attached to the end of the spring is 2.5kg, what is he spring constant of the spring?What is the maximum elastic potential energy of the system when the spring is fully compressed?

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Asked Jun 18, 2019
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the position of a mass hanging from a spring as it oscillates has the form x(t)=0.2cos(6.7t). (All quantities given are in standard units). 

If the mass attached to the end of the spring is 2.5kg, what is he spring constant of the spring?

What is the maximum elastic potential energy of the system when the spring is fully compressed?

 

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Expert Answer

Step 1

The position of a mass hanging from a spring is given below.

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x(t)0.2 cos (6.7t) here, t is the time]

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Step 2

(a)Write the standard expression for the position of  an oscillating system.

 

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here,A is the amplitude, x(t) A cos(at) (II) wis the angular frequency,

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Step 3

Compare equation (I) and (II), to get the ...

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A 0.2m D 6.7 rad/s

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