A 40.0 mL solution of 0.100 mol/L acetic acid, CH3COOH (K, = 1.8 x 10), titrated with 0.100 mol/L sodium hydroxide at 25°C. Write the net ionic equation for this titration: NaOH + CH;COOH + CH;COON + H,0 NaOH + CH,COOH → CH;COONA + H,0 OH-+ CH,COOH → CH;COO- + H,0 OH- + CH,COOH → CH;COO + H,0 А. В. с. D. E. OH-+ H* > H20 F. OH-+ H* + H,0

A 40.0 mL solution of 0.100 mol/L acetic acid, CH3COOH (K, = 1.8 x 10), titrated with 0.100 mol/L sodium hydroxide at 25°C. Write the net ionic equation for this titration: NaOH + CH;COOH + CH;COON + H,0 NaOH + CH,COOH → CH;COONA + H,0 OH-+ CH,COOH → CH;COO- + H,0 OH- + CH,COOH → CH;COO + H,0 А. В. с. D. E. OH-+ H* > H20 F. OH-+ H* + H,0

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter17: Complexation And Precipitation Reactions And Titrations

Section: Chapter Questions

Problem 17.24QAP

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