Calculate the moles of KHP titrated in each trial = M x L = 0.5 M x 0.025 L=_____ Calculate the moles of NaOH using stoichiometry of the reaction KC8H5O4 + NaOH ® NaKC8H4O4 + H2O Mole of NaOH = mole of KHP x = ______________________ Calculate the molarity of NaOH for each trial: molarity of NaOH = . Enter your answers in the following Table 2 Table 2: molarity of NaOH solution. 1st trial 2nd trial 3rd trial 4th trial Molarity of NaOH Average Molarity

Calculate the moles of KHP titrated in each trial = M x L = 0.5 M x 0.025 L=_ Calculate the moles of NaOH using stoichiometry of the reaction KC8H5O4 + NaOH ® NaKC8H4O4 + H2O Mole of NaOH = mole of KHP x = __________________ Calculate the molarity of NaOH for each trial: molarity of NaOH = . Enter your answers in the following Table 2 Table 2: molarity of NaOH solution. 1st trial 2nd trial 3rd trial 4th trial Molarity of NaOH Average Molarity

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter15: Additional Aqueous Equilibria

Section: Chapter Questions

Problem 42QRT: Calculate the volume of 0.225-M NaOH required to titrate to the equivalence point for each of these...

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Calculate the volume of 0.225-M NaOH required to titrate to the equivalence point for each of these samples. (a) 20.0 mL of 0.315-M HBr (b) 30.0 mL of 0.250-M HClO4 (c) 6.00 g of concentrated acetic acid, CH3COOH, which is 99.7% pure
2.1 20.00 mL of 0.0750 M benzoic acid ( C6H5COOH) is titrated with 0.0250 M NaOH. Ka benzoic acid = 6.5 x 10-5 A. How many mmol of benzoate ion is present after the addition of 40.00 mL NaOH? B.How many mL of NaOH will produce the same concentration of the benzoic acid and benzoate? C What is the concentration of the benzoic acid after the addition of 50.00 mL of NaOH?
Determining the ksp of Calcium Hydrioxides Titration of Calcium Hydroxide with HCl Mass of Erlenmeyer flask: 25.52 g Mass of Erlenmeyer Flask + Calcium Hydroxide Solution (lime water) (g): 28.44 g Mass of Calcium Hydroxide Solution (g): 2.92 g Volume of Ca(OH)2 Density = 1.000 g/mL (mL) - 2.92 mL Concentration of HCl (M) - How do you find this? HCl 0.10 M solution used Initial HCl volume = 0.79 mL Final HCl volume = 0.09 mL volume of HCl delivered = 0.70 mL Moles of HCl delieverd - how do I calculate this? Moles of OH- in sample - how do I calculate this? Moles of Ca2+ in sample - how do I calculate this? Thank you!
Determining the ksp of Calcium Hydrioxides Titration of Calcium Hydroxide with HCl Mass of Erlenmeyer flask: 25.52 g Mass of Erlenmeyer Flask + Calcium Hydroxide Solution (lime water) (g): 28.44 g Mass of Calcium Hydroxide Solution (g): 2.92 g Volume of Ca(OH)2 Density = 1.000 g/mL (mL) - 2.92 mL Concentration of HCl (M) - How do you find this? HCl 0.10 M solution used Initial HCl volume = 0.79 mL Final HCl volume = 0.09 mL volume of HCl delivered = 0.70 mL Moles of HCl delieverd - 0.07 x 10^-3 mol Moles of OH- in sample - 0.07 x 10^-3 mol Moles of Ca2+ in sample - 0.035 x 10^-3 mol How do I calculate molar solubility and ksp? Thanks!!
A student performed three H2SO4 titrations in Part 2 using their 0.1048 M NaOH solution which they previously standardized in Part 1. They reported the following measurements: Determination #1 Determination #2 Determination #3 Final NaOH Burette Reading 37.65 mL 28.35 mL 26.23 mL Initial NaOH Burette Reading 12.80 mL 4.05 mL 1.73 mL For every 1 mole of H2SO4, how many moles of NaOH are needed to reach equivalence in the titration? Report the integer number only (no units).
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2.5 20.00 mL of 0.0750 M benzoic acid ( C6H5COOH) is titrated with 0.0250 M NaOH. Ka benzoic acid = 6.5 x 10-5 A.What is the pH of the solution after the addition of 10.00 mL NaOH? B.What is the concentration of benzoic acid after the addition of 40.00 mL NaOH?
How many mL of 0.1200 M KSCN will be needed in the back titration after addition of 30 mL 0.110 M AgNO3 solution to 0.3655g KI dissolved in 100 mL water? a. 1.1951 mL b. 5.1919 mL c. 9.1519 mL d. 1.5911 mL
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What is the pH at the second equivalence point in the titration of 541 mL of 0.501M carbonic acid with 1.1M NaOH? Ka1=4.03x10-7, Ka2=5.6x10-11. Thank you
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2. 20.00 mL of 0.0750 M benzoic acid ( C6H5COOH) is titrated with 0.0250 M NaOH. Ka benzoic acid = 6.5 x 10-5 a. What is the hydronium ion concentration? B. What is the initial pH of the benzoic acid ? C. What is the concentration of the benzoate ion after the addition of 25.00 mL of NaOH? D.