Question
Asked Jan 31, 2019

A 45.2 mg sample of phosphorus reacts with selenium to form 131.6mg of the selenide. Determine the empirical formula of phosphorus selenide.

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Step 1

Phosphorous have +3 charge while the charge on selenium may be -2 or -4. Therefore, the charge on Se assumed to be x which give the formula of phosphorous selenide as PxSe3.

Step 2

Phosphorous on reacting with selenium produces phosphorous selenide as follows:

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Step 3

number of mole of phosphorus /number of mole of phosphorus s...

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