A 47.00 ml aliquot from a 0.490 L solution that contains 0.410 g of MnSO, (MW = 151.00 g/mol) required 40.7 mL of an EDTA solution to reach the end point in a titration. What mass, in milligrams, of CaCO, ( MW = 100.09 g/mol) will react with 1.61 ml. of the EDTA solution? mass: mg

Chemical Principles in the Laboratory
11th Edition
ISBN:9781305264434
Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Chapter28: Determination Of The Hardness Of Water
Section: Chapter Questions
Problem 3ASA: A 100-mL sample of hard water is titrated with the EDTA solution in Problem 2. The same amount of...
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A 47.00 ml aliquot from a 0.490 L solution that contains 0.410 g of MnSO, (MW = 151.00 g/mol) required 40.7 mL of an
EDTA solution to reach the end point in a titration. What mass, in milligrams, of CaCO, ( MW = 100.09 g/mol) will react
with 1.61 ml. of the EDTA solution?
mass:
mg
Transcribed Image Text:A 47.00 ml aliquot from a 0.490 L solution that contains 0.410 g of MnSO, (MW = 151.00 g/mol) required 40.7 mL of an EDTA solution to reach the end point in a titration. What mass, in milligrams, of CaCO, ( MW = 100.09 g/mol) will react with 1.61 ml. of the EDTA solution? mass: mg
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