Asked Mar 25, 2019

A 50.0 kg crate is being pulled along a horizontal smooth surface. The pulling force is 10.0 n and is directed 20.0 degrees above the horizontal. What is the magnitude of the acceleration of the crate?


Expert Answer

Step 1

The acceleration is due to the horizontal component of the force. This, the equation for the acceleration is,

Step 2

Substituting the...


Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in



Newtons Laws of Motion

Related Physics Q&A

Find answers to questions asked by student like you

Show more Q&A add

Q: 10) Based on the vibrating string experiment answer questions below as increase decrease orremains t...

A: (a)Write the expression for fundamental frequency of the string.


Q: In the figure the current in resistance 6 is i6 = 1.33 A and the resistances are R1 = R2 = R3 = 1.57...

A: To find the emf in the battery , compute emf in each loop.


Q: Please help

A: Given,


Q: How to find v2 in the equation : KE= 1/2mv2

A: The expression for Kinetic energy is.


Q: In the figure, two long straight wires are perpendicular to the page and separated by distance d1 = ...

A: Let us say that, the magnetic field due to wire 1 at point P is B1 and that due to wire 2 is B2. The...


Q: Please show me how to work this. Don't round any figures please.

A: The work done can be calculated using following steps:Given:


Q: Water falls without splashing at a rate of 0.310 L/s from a height of 3.10 m into a 0.710-kg bucket ...

A: The scale after 2.90 s after water start accumulating it is calculated in following steps.Given:Mass...


Q: A 44.1-kg crate rests on a horizontal floor, and a 66.9-kg person is standing on the crate. Determin...

A: (a)Normal force exerted by the floor on the crate is,


Q: Say you take a photograph of night sky on October 1, 2018 at 11:00:00 pm. At what time you'd take an...

A: In class we learned a difference between solar and sidereal day - for each orbit around the Sun, a p...