A 50.00-mL aliquot of 0.0700M NACN is titrated with 0.140 M HCI. The reaction is: CN- (aq) + H3O* (aq) HCN (aq) + H2O () Calculate the pH after the addition of HCI: 0.00 mL 10.00 mL 12.50 mL 25.00 mL 26.00 mL Ka for HCN = 6.20 x 10*10

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter15: Additional Aqueous Equilibria
Section: Chapter Questions
Problem 93QRT: When 40.00 mL of a weak monoprotic acid solution is titrated with 0.100-M NaOH, the equivalence...
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PLEASE ANSWE 12.5, 25, AND 26

A 50.00-mL aliquot of 0.0700 M NaCN is titrated with 0.140 M HCI. The reaction is:
CN' (aq) + H3O* (aq)
HCN (aq) + H2O ()
Calculate the pH after the addition of HCI:
0.00 mL
10.00 mL
12.50 mL
25.00 mL
26.00 mL
Ka for HCN = 6.20 x 10-10
Transcribed Image Text:A 50.00-mL aliquot of 0.0700 M NaCN is titrated with 0.140 M HCI. The reaction is: CN' (aq) + H3O* (aq) HCN (aq) + H2O () Calculate the pH after the addition of HCI: 0.00 mL 10.00 mL 12.50 mL 25.00 mL 26.00 mL Ka for HCN = 6.20 x 10-10
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