A 520 kg cannon fires a 5.6 kg cannon ball horizontally.  The recoil speed of the cannon at the moment of firing is 3.2 m/s.  The cannon is free to move horizontally.  [Ignore effects of gravity, friction, and drag.]Can you explain how to get the speed of cannon ball? [Conservatoin of energy momentum...something about before and after]]

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Asked Oct 18, 2019
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A 520 kg cannon fires a 5.6 kg cannon ball horizontally.  The recoil speed of the cannon at the moment of firing is 3.2 m/s.  The cannon is free to move horizontally.  

[Ignore effects of gravity, friction, and drag.]

Can you explain how to get the speed of cannon ball? [Conservatoin of energy momentum...something about before and after]]

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Expert Answer

Step 1
Given
Mam of Cannon, M = 520 kg
MaM of Connon bal, m- 56 kg
Initial velocity of Canon, U o
Iniial velocity of Cannon ball, o
Final velotihy of Cannon, V, = 3.2 m (Figt)
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Given Mam of Cannon, M = 520 kg MaM of Connon bal, m- 56 kg Initial velocity of Canon, U o Iniial velocity of Cannon ball, o Final velotihy of Cannon, V, = 3.2 m (Figt)

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Step 2
From the Conservatiom of momentum
Tnitial momentum
Finao momentum
MV m2
MU +mU
the velocity of cannon ball.
where, 2
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From the Conservatiom of momentum Tnitial momentum Finao momentum MV m2 MU +mU the velocity of cannon ball. where, 2

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Step 3
Since, u=Uzo Aimpli the above euation
MVi
V2=
-(520 k)
(22 mls)
(5.6 169)
- - 297.14mls ( left)
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Since, u=Uzo Aimpli the above euation MVi V2= -(520 k) (22 mls) (5.6 169) - - 297.14mls ( left)

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