A 75 kg person doing light work requires about 3000 kcal of food energy perday, 40% of which is actually used by the body’s cells. (The other 60% is lostas heat and in waste products.) Before being used by the cells, effectively allof this energy is stored in ATP, which is then cleaved into ADP and PO3−2 , with the release of 12.5 kcal per mole of ATP.(a) How many moles of ATP are turned over per day in this fashion? Whatmass of ATP does this correspond to? (The molecular weight of ATP is507 g/mol.)(b) The body actually contains approximately 5 g ATP. Estimate the averagerecycle time for an ATP molecule. You see that it is much more efficientto reuse ADP rather than to synthesize it de novo (from scratch).

A 75 kg person doing light work requires about 3000 kcal of food energy perday, 40% of which is actually used by the body’s cells. (The other 60% is lostas heat and in waste products.) Before being used by the cells, effectively allof this energy is stored in ATP, which is then cleaved into ADP and PO3−2 , with the release of 12.5 kcal per mole of ATP.(a) How many moles of ATP are turned over per day in this fashion? Whatmass of ATP does this correspond to? (The molecular weight of ATP is507 g/mol.)(b) The body actually contains approximately 5 g ATP. Estimate the averagerecycle time for an ATP molecule. You see that it is much more efficientto reuse ADP rather than to synthesize it de novo (from scratch).

Human Physiology: From Cells to Systems (MindTap Course List)

9th Edition

ISBN:9781285866932

Author:Lauralee Sherwood

Publisher:Lauralee Sherwood

Chapter2: Cell Physiology

Section: Chapter Questions

Problem 2SQE

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Similar questions

if an 8.4-oz (250 mL) energy drink can has 27 grams of sugar, calculate the moles of ATP produced in the body when 1 oz of the drink is consumed assuming all the sugars in 1 oz of the drink are composed of only glucose.
How many ATP molecules could maximally be generated from one molecule of glucose, if the complete oxidation of 1 mole of glucose to CO2 and H2O yields 686 kcal of free energy and the useful chemical energy available in the high- energy phosphate bond of 1 mole of ATP is 12 kcal?
Why is it 30 to 32 ATP produced for cellular respiration in Physiology? When I calculate it, I get 32.
A camel hump contains 12 kg of triacylgylcerols. (a) Given that there are 0.491 moles of ATP per gram of fat, how many moles of ATP could be produced by the fat in the camel hump?(b) If the hydrolysis of ATP releases 7.3 kcal/mole, how many kilocalories are produced by the utilization of the fat?
A 70-kg adult human (154 lb) could meet his orher entire energy needs for one day by eating 3 moles ofglucose (540 g). (We do not recommend this.) Each mol-ecule of glucose generates 30 molecules of ATP when it isoxidized to CO2. The concentration of ATP is maintained incells at about 2 mM, and a 70-kg adult has about 25 litersof intracellular fluid. Given that the ATP concentrationremains constant in cells, calculate how many times perday, on average, each ATP molecule in the body is hydro-lyzed and resynthesized.
The hydrolysis of the phosphoester bond of ATP releases a large amount of free energy. True or false?
A total of 30.5 kJ mol-1 of free energy is needed to synthesise ATP from ADP and Pi when the reactants and products are at 1.0 M concentrations and the temperature is 25oC. Because the actual physiological concentrations of ATP, ADP, and Pi are not 1.0 M, and the temperature is 37oC, the free energy required to synthesise ATP under physiological conditions is actually ~ 46.2 kJ mol-1. A 68 kg adult requires an energy intake of 8,550 kJ of food per day (24 hours). Calculate the mass (in Kg) of ATP synthesised by a human adult in 24 hours, assuming that the percentage efficiency of converting inputted calories in ATP is 50%. What percentage of the body weight does this represent?
Consider the following chemical reaction: Glucose + ATP → Glucose-6-Phosphate + ADP + Pi Given the following information, calculate the actual free energy change (G’) of this reaction. G’ of Glucose + ATP → Glucose-6-Phosphate + ADP + Pi = -16.7 kJ/mol [Glucose] = 5.0 mM [ATP] = 1.85 mM [Glucose-6-Phosphate] = 0.083 mM [ADP] = 0.14 mM [Pi] = 1.0 mM Temperature = 37 C R (Gas Constant) = 8.314 J/mol•K
The hydrolysis of ATP to yield AMP and PPi yields_____________ kJ/mol
Calculate the actual, physiological ΔG for the reaction at 37 °C, as it occurs in the cytosol of neurons, with phosphocreatine at 4.7 mM, creatine at 1.0 mM, ADP at 0.73 mM, and ATP at 2.6 mM.
The complete combustion of palmitate and glucose yields 9781 kJ ∙ mol−1 and 2850 kJ ∙ mol−1 of free energy, respectively. Compare these values to the free energy (as ATP) obtained though catabolism of palmitate and glucose under standard conditions. Which process is more efficient?
What are the usual ionic forms of ATP and ADP in typical cells? Does this information have any bearing on the free-energy change for the conversion of ATP to ADP?