please do both On average, 180 liters of plasma are filtered each day.A If humans had to expend one molecule of ATP for every molecule of water retained, approximately how many molecules of ATPwould be required?6.022x10*27molesB. If 36 molecules of ATP are produced by the aerobic catabolism of one molecule of glucose, how many grams of glucose would berequired?Sx10^4grams

An important "energy molecule" found in every living organism, adenosine 5′-triphosphate is…

Answered: On average, 180 liters of plasma are…

Human Physiology: From Cells to Systems (MindTap Course List)

9th Edition

ISBN:9781285866932

Author:Lauralee Sherwood

Publisher:Lauralee Sherwood

Chapter2: Cell Physiology

Section: Chapter Questions

Problem 2SQE

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Similar questions

Why is it 30 to 32 ATP produced for cellular respiration in Physiology? When I calculate it, I get 32.
Please calculate the ΔG of glucose transport into the cell if the concentration of glucose is 1mM inside the cell and 100μM outside. R=2cal/mol*K and T = 300K. A. 1.38kcal/mol B. -1.38kcal/mol C. 2.76kcal/mol D. -2.76kcal/mol
A 70-kg adult human (154 lb) could meet his orher entire energy needs for one day by eating 3 moles ofglucose (540 g). (We do not recommend this.) Each mol-ecule of glucose generates 30 molecules of ATP when it isoxidized to CO2. The concentration of ATP is maintained incells at about 2 mM, and a 70-kg adult has about 25 litersof intracellular fluid. Given that the ATP concentrationremains constant in cells, calculate how many times perday, on average, each ATP molecule in the body is hydro-lyzed and resynthesized.
Calculate the actual, physiological ΔG for the reaction at 37 °C, as it occurs in the cytosol of neurons, with phosphocreatine at 4.7 mM, creatine at 1.0 mM, ADP at 0.73 mM, and ATP at 2.6 mM.
if an 8.4-oz (250 mL) energy drink can has 27 grams of sugar, calculate the moles of ATP produced in the body when 1 oz of the drink is consumed assuming all the sugars in 1 oz of the drink are composed of only glucose.
If, in addition to the constraints on glucose concentration listed previously, we have in the liver cell ATP concentration = 5 mM and ADP concentration = 5 mM , what is the theoretical concentration of glucose-6-phosphate at equilibrium at pH=7.4 and 37 ∘C ? Express your answer to three significant figures and include the appropriate units. Please type answer note write by hend.
A total of 30.5 kJ mol-1 of free energy is needed to synthesise ATP from ADP and Pi when the reactants and products are at 1.0 M concentrations and the temperature is 25oC. Because the actual physiological concentrations of ATP, ADP, and Pi are not 1.0 M, and the temperature is 37oC, the free energy required to synthesise ATP under physiological conditions is actually ~ 46.2 kJ mol-1. A 68 kg adult requires an energy intake of 8,550 kJ of food per day (24 hours). Calculate the mass (in Kg) of ATP synthesised by a human adult in 24 hours, assuming that the percentage efficiency of converting inputted calories in ATP is 50%. What percentage of the body weight does this represent?
sixteen milligram of gluecose were eaten by the bacteria Sanacoccus pumasarious. calculate the hypothetical amount of Atp your patient can generate under aerobic respiration with this amount of glucose glucose MW=180.16g/mol ;1mol=6.02x10^23
How many net ATPs would be produced if the following fatty acid is completely oxidized intocarbon dioxides and water? 94.5 96.5 98 98.5 108
If Eric ran at 80% of his aerobic capacity for 1.5hrs/day, 3 days per week, how many MET-min per week would he be accumulating?
A) weight of ATP used in human adult in 24hr Calculated 69.2 kg B) Help - percentage of the persons body weight that this represents?
Consider the following chemical reaction: Glucose + ATP → Glucose-6-Phosphate + ADP + Pi Given the following information, calculate the actual free energy change (G’) of this reaction. G’ of Glucose + ATP → Glucose-6-Phosphate + ADP + Pi = -16.7 kJ/mol [Glucose] = 5.0 mM [ATP] = 1.85 mM [Glucose-6-Phosphate] = 0.083 mM [ADP] = 0.14 mM [Pi] = 1.0 mM Temperature = 37 C R (Gas Constant) = 8.314 J/mol•K

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