A 75.0-mL volume of 0.200 M NH3 (K = 1.8 x 10-5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 21.0 mL of HNO3-

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Chapter7: Neutralization Titrations And Graphical Representations
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A 75.0-mL volume of 0.200 M NH3 (K, = 1.8 × 10-5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 21.0 mL of HNO3-
Express your answer numerically.
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Eν ΑΣφ
pH =
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Transcribed Image Text:A 75.0-mL volume of 0.200 M NH3 (K, = 1.8 × 10-5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 21.0 mL of HNO3- Express your answer numerically. • View Available Hint(s) Eν ΑΣφ pH = Submit
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