A 9-kg block is suspended from a spring having a stiffness of k = 200 N/m. If the block is given an upward velocity of 0.4 m/s when it is 95 mm above its equilibrium position, determine the equation which describes the motion. Assume that positive displacement is downward. O x = 0.073 sin (5.77t) + 0.08 cos (5.77t) O x = 0.07 sin (5.77t) - 0.075 cos (5.77t) O x = -0.0693 sin (5.77t) - 0.075 cos (5.77t) O x = 0.07 sin (5.77t) - 0.08 cos (5.77t) Ox= -0.0849 sin (5.77t) - 0.095 cos (5.77t) x = 0.0693 sin (5.77t) + 0.075 cos (5.77t)

A 9-kg block is suspended from a spring having a stiffness of k = 200 N/m. If the block is given an upward velocity of 0.4 m/s when it is 95 mm above its equilibrium position, determine the equation which describes the motion. Assume that positive displacement is downward. O x = 0.073 sin (5.77t) + 0.08 cos (5.77t) O x = 0.07 sin (5.77t) - 0.075 cos (5.77t) O x = -0.0693 sin (5.77t) - 0.075 cos (5.77t) O x = 0.07 sin (5.77t) - 0.08 cos (5.77t) Ox= -0.0849 sin (5.77t) - 0.095 cos (5.77t) x = 0.0693 sin (5.77t) + 0.075 cos (5.77t)

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter7: Conservation Of Energy

Section: Chapter Questions

Problem 15P: A block of mass m = 2.00 kg is attached to a spring of force constant k = 500 N/m as shown in Figure...

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