abAbsolute standard deviation =Coefficient of variation =y = 1.20 (+0.02) x 10-8-3.60(±0.2) × 10-⁹xResult =Absolute standard deviation =Coefficient of variation =CResult =dy=90.95 (±0.08) - 89.40(±0.06) +0.200(+0.004)Absolute standard deviation ==Coefficient of variation =Result =±y=y = 0.0040 (+0.0005) x 10.28 (+0.02) × 395(+1)Result =±Absolute standard deviation =Coefficient of variation =%329(+0.03) x 10-141.47 (+0.04) x 10-16%%H%±

Given : y=1.20±0.02×10-8-3.60±0.2×10-9 To Find : i Absolute standard deviationiiCoefficients of…

Answered: а a y = 1.20 (+0.02) x Absolute…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Mean of x And standard deviation of x

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а a y = 1.20 (+0.02) x Absolute standard deviation = Coefficient of variation = Result = 10-8-3.60(+0.2) x× 10-⁹ % H