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- Mutiple Answers Which of the following matches regexp /(very )+(fat )?(tall|ugly) man/a) very fat manb) fat tall manc) very very fat ugly mand) very very very tall man Please Answer With Detailed Explanation!Finish code in Mathematica: The representations of HMMs is also the same. Here's what a call to readHMM[] would look like: hmmObject = readHMMFile["Test/humanMalaria.hmm"]= hmmObject$4958, hmmObject["states"]={"M", "H"} hmmObject["initialStateProbs"]={0.5, 0.5} hmmObject["transitionMatrix"]={{0.5, 0.5}, {0.5, 0.5}} hmmObject["alphabet"]={"A", "C", "G", "T"} hmmObject["emissionMatrix"]={{0.3, 0.25}, {0.2, 0.25}, {0.2, 0.25}, {0.3, 0.25}} observationSeq_ is like: {1, 4, 3, 1, 4, 4, 4, 3, 3, 2, 3, 2, 2, 3, 2} You will have two: buildForwardMatrix and buildBackwardMatrix. You will then combine them inside posteriorProbabilities. posteriorDecode calls posteriorProbabilities and uses the result to find the posterior path and output the corresponding state names. Finish the following four functions in Mathematica: buildForwardMatrix[observationSeq_, hmm_] := Module[{numberOfObservations, numberOfStates, forwardMatrix, observationIndex}, (* Put your code for bulding the forward matrix here.…A finite sequence of symbols from a given alphabet will be called a string over the alphabet. A string that consists of a sequence a1, a2, a3, a4, … … … … , an of symbols will be denoted by the juxtaposition a1 a2 a3 a4 … … … … an. Given the strings: u = a2bab2and v = bab2, Evaluate the following operations for strings: (i) ԑu(ii) u + v(iii) u(u| v)(iv) v | (v | u)
- Trace and document every step of execution of the following program: public class Trace { public static void main(String[] args) { int[] num = {1, 3, 6, 9, 12 }; for (int i = 4; i >= 0; i--) { num[i] +=1; } num[0] *=num[4]; } }Correct answer will be upvoted else Multiple Downvoted. Computer science. inquiry is depicted by a couple of integers li, ri (1≤li<ri≤n). For each question, he needs to decide if there exists a decent aftereffect in s that is equivalent to the substring s[li… ri]. A substring s[i… j] of a string s is the string shaped by characters sisi+1… sj. String an is supposed to be an aftereffect of string b if a can be gotten from b by erasing a few characters without changing the request for the excess characters. An aftereffect is supposed to be acceptable in case it isn't coterminous and has length ≥2. For instance, in the event that s is "1100110", the aftereffects s1s2s4 ("1100110") and s1s5s7 ("1100110") are acceptable, while s1s2s3 ("1100110") isn't acceptable. Would you be able to help Hr0d1y answer each question? Input The primary line of the input contains a solitary integer t (1≤t≤100) — the number of experiments. The portrayal of each experiment is as per the…I got an error message for the answer Bartleby gave me last night as follows Input Answer alphabet = "abcdefghijklmnopqrstuvwxyz"test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]def histogram(s):d=dict()for c in s:if c not in d:d[c]=1 else:d[c]+=1return d;def has_duplicate(string):# return false if each letter in s is not distincth=histogram(string)for k,v in h.items():if v>1:return truereturn falsefor string in test_dups:if has_duplicate(string):printf(string,"has duplicates")else:print(string,"has no duplicates")def main():test_dups_loop()if_name=='_main_'main() THE ERROR MESSAGE said ***TRUE NEEDS TO BE DEFINED. this is all I need from the answer code I received.
- 2. Using Java notation, suppose A is the alphabet {'a','b','c' }List the labels of all strings in A* from among thefollowing. a. "" b. "aa" c. "bb" d. "abc"e. "abcd" f. "aaaaaaaa..." (an infinite string ofa's) -> (THIS IS THE PROBLEM #3) <- 3. For alphabet A of the last problem, how many length 4stringsare there in A*?a. 3 b. 4 b. 12 c. 27 d. 81 e. 64 f. 128create a 2 tape Turing machine (use JFLAP) that has on tape 1 the alphabet of a,b,null, on tape 2 the alphabet is 0,1,2,3, null. Tape 1 has initial content of (a+b)*, Tape 2 has initial content of (0+1)* Begin by processing tape 1, if the substring aa is found on tape 1, search tape 2 for the first 00 substring and replace it with 22 if the substring bb is found on tape 1, search tape 2 for the first 11 substring and replace it with 33. If at anytime aa does not have a matching 00 reject if at anytime bb does not have a matching 11 reject else accept after all of tape 1 has been processed.Euclid’s algorithm (or the Euclidean algorithm) is an algorithm that computes thegreatest common divisor, denoted by gcd, of two integers. Below are the original versions ofEuclid’s algorithm that uses repeated subtraction and another one that uses the remainder.int gcd_sub(int a, int b){ if (!a) return b; while (b) if (a > b) a = a – b; else b = b – a; return a;}int gcd_rem(int a, int b){ int t; while (b) { t = b; b = a % b; a = t; } return a;}1. Trace each of the above algorithm using specific values for a and b.2. Compare both algorithms.
- 13. p(x): x is intelligent q(x): x reads book r(x): x is a student in your class Find the correct English translation for the following logical expression: ∀x(r(x)→(p(x) Λ q(x)) a. None b. There is an intelligent student in your class who reads book c. Every student in your class is intelligent and reads book d. All student in your class is intelligent and doesn't read bookRegular expressions are built recursively out of smaller regular expressions, using some rules described below. Each regular expression ?denotes a language ?(?), which is also defined recursively from the languages denoted by ?′? subexpressions. Given an alphabet ∑ = {0, 1}, write the language denoted by the following regular expressions:(i) 1(ii) 0 | 1(iii) (0 | 1)(iv) (0 | 1)∗(v) 1(0 | 1)∗(vi) 0 |1 (0| 1)Blackout Math is a math puzzle in which you are given an incorrect arithmetic equation. The goal of the puzzle is to remove two of the digits and/or operators in the equation so that the resulting equation is correct. For example, given the equation 6 - 5 = 15 ^ 4/2we can remove the digit 5 and the / operator from the right-hand side in order to obtain the correct equality 6 - 5 = 1 ^ 42. Both sides of the equation now equal to 1. Observe how removing an operator between two numbers (4 and 2) causes the digits of the numbers to be concatenated (42). Here is a more complicated example: 288 / 24 x 6 = 18 x 13 x 8 We can remove digits and operators from either side of the equals sign (either both from one side, or one on each side). In this case, we can remove the 2 from the number 24 on the left-hand side and the 1 from the number 13 on the right-hand side to obtain the correct equality 288 / 4 x 6 = 18 x 3 x 8 Both sides of the equation now equal to 432. Here is another puzzle for you…