A block of mass m = 5 Kg is attached to a spring of spring constant k. The block oscillates in simple harmonic motion on a frictionless horizontal surface. The block-spring total mechanical energy is 22.5 J. The maximum velocity of block, vmax, is: 2.1 m/s 1.8 m/s 3 m/s O 2.4 m/s O 3.8 m/s

A block of mass m = 5 Kg is attached to a spring of spring constant k. The block oscillates in simple harmonic motion on a frictionless horizontal surface. The block-spring total mechanical energy is 22.5 J. The maximum velocity of block, vmax, is: 2.1 m/s 1.8 m/s 3 m/s O 2.4 m/s O 3.8 m/s

Name: A block of mass m =5 Kg is attached to a spring of spring constant k.
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Description: A block of mass m =5 Kg is attached to a spring of spring constant k. The blockoscillates in simple harmonic motion ona frictionless horizontal surface. Theblock-spring total mechanical energy is 22.5 J. The maximum velocity of block,vmax, is:O 2.1

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter12: Oscillatory Motion

Section: Chapter Questions

Problem 16P: A blockspring system oscillates with an amplitude of 3.50 cm. The spring constant is 250 N/m and the...

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A horizontal block-spring system with the block on a frictionless surface has total mechanical energy E = 47.0 J and a maximum displacement from equilibrium of 0.240 m. (a) What is the spring constant? (b) What is the kinetic energy of the system at the equilibrium point? (c) If the maximum speed of the block is 3.45 m/s, what is its mass? (d) What is the speed of the block when its displacement is 0.160 m? (e) Find the kinetic energy of the block at x = 0.160 m. (f) Find the potential energy stored in the spring when x = 0.160 m. (g) Suppose the same system is released from rest at x = 0.240 m on a rough surface so that it loses 14.0 J by the time it reaches its first turning point (after passing equilibrium at x = 0). What is its position at that instant?
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